到底long型如何转成String类型

wolfsmoke 2001-05-14 03:55:00
rs.getLong读出一个long型数据
不知如何,付给一个String类型的变量
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coaa 2001-05-15
斑竹就是心细啊!
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skyyoung 2001-05-14
integer to String : int i = 42;
String str = Integer.toString(i);
or
String str = "" + i



double to String : String str = Double.toString(i);



long to String : String str = Long.toString(l);



float to String : String str = Float.toString(f);




String to integer : str = "25";
int i = Integer.valueOf(str).intValue();
or
int i = Integer.parseInt(str);



String to double : double d = Double.valueOf(str).doubleValue();



String to long : long l = Long.valueOf(str).longValue();
or
long l = Long.parseLong(str);



String to float : float f = Float.valueOf(str).floatValue();




decimal to binary : int i = 42;
String binstr = Integer.toBinaryString(i);




decimal to hexadecimal : int i = 42;
String hexstr = Integer.toString(i, 16);
or
String hexstr = Integer.toHexString(i);




hexadecimal (String) to integer : int i = Integer.valueOf("B8DA3", 16).intValue();
or
int i = Integer.parseInt("B8DA3", 16);





ASCII code to String int i = 64;
String aChar = new Character((char)i).toString();




integer to ASCII code (byte) char c = 'A';
int i = (int) c; // i will have the value 65 decimal




To extract Ascii codes from a String String test = "ABCD";
for ( int i = 0; i < test.length(); ++i ) {
char c = test.charAt( i );
int i = (int) c;
System.out.println(i);
}




integer to boolean b = (i != 0);



boolean to integer i = (b)?1:0;



note :To catch illegal number conversion, try using the try/catch mechanism. try{
i = Integer.parseInt(aString);
}
catch(NumberFormatException e)
{
}



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