一个排序如题的咨询.

[MasterChen]

CREATE TABLE [dbo].[USER_BAOMING] (
[身份证号] [varchar] (20) COLLATE Chinese_PRC_CI_AS NOT NULL ,
[姓名] [nvarchar] (100) COLLATE Chinese_PRC_CI_AS NULL ,
[性别] [char] (1) COLLATE Chinese_PRC_CI_AS NULL ,
[出生日期] [datetime] NULL ,
[工作单位] [nvarchar] (200) COLLATE Chinese_PRC_CI_AS NULL ,
[职务职称] [varchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,
[是否离退休] [varchar] (20) COLLATE Chinese_PRC_CI_AS NULL ,
[岗位系列] [varchar] (20) COLLATE Chinese_PRC_CI_AS NULL ,
[是否置换区职工] [varchar] (20) COLLATE Chinese_PRC_CI_AS NULL ,
[是否双职工] [varchar] (20) COLLATE Chinese_PRC_CI_AS NULL ,
[备注] [varchar] (1000) COLLATE Chinese_PRC_CI_AS NULL ,
[审核标志] [varchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,
[电子邮件] [varchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,
[手机座机] [varchar] (100) COLLATE Chinese_PRC_CI_AS NULL ,
[得分] [varchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,
[排队方式] [varchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,
[座机] [varchar] (100) COLLATE Chinese_PRC_CI_AS NULL
) ON [PRIMARY]
GO


表结构如上，现要进行一个排队，其中有一个字段为 是否离退休
如果否，即为该同志“在职”，在其它表中代码为: 1010,如果是，代码为1000,
现在职与离退休要穿叉排队，比例为5:1，即5名在职职工后穿叉一名离退休职工，请问此如何进行，请各位帮帮忙，谢谢了。

[dawugui]

if object_id('pubs..tb') is not null
drop table tb
go

create table tb(身份证号 varchar(18) , 是否离退休 varchar(4))
insert into tb(身份证号,是否离退休) values('00000000000000000','1010')
insert into tb(身份证号,是否离退休) values('00000000000000001','1010')
insert into tb(身份证号,是否离退休) values('00000000000000002','1010')
insert into tb(身份证号,是否离退休) values('00000000000000003','1010')
insert into tb(身份证号,是否离退休) values('00000000000000004','1010')
insert into tb(身份证号,是否离退休) values('00000000000000005','1010')
insert into tb(身份证号,是否离退休) values('00000000000000006','1010')
insert into tb(身份证号,是否离退休) values('00000000000000007','1010')
insert into tb(身份证号,是否离退休) values('00000000000000008','1010')
insert into tb(身份证号,是否离退休) values('00000000000000009','1010')
insert into tb(身份证号,是否离退休) values('10000000000000000','1000')
insert into tb(身份证号,是否离退休) values('20000000000000000','1000')
go

select px = identity(int,1,1) , * into tb1 from tb where 是否离退休 = '1010' order by 身份证号
select px = identity(int,1,1) , * into tb2 from tb where 是否离退休 = '1000' order by 身份证号

select 身份证号,是否离退休 from
(
select (px-1)/5 + 1 px , 身份证号,是否离退休 from tb1
union all
select * from tb2
) t
order by px , 身份证号
drop table tb,tb1,tb2

/*
身份证号 是否离退休
------------------ -----
00000000000000000 1010
00000000000000001 1010
00000000000000002 1010
00000000000000003 1010
00000000000000004 1010
10000000000000000 1000
00000000000000005 1010
00000000000000006 1010
00000000000000007 1010
00000000000000008 1010
00000000000000009 1010
20000000000000000 1000

（所影响的行数为 12 行）
*/

[OracleRoob]

--借用楼上数据



create table tb(身份证号 varchar(18) , 是否离退休 varchar(4))
insert into tb(身份证号,是否离退休) values('00000000000000000','1010')
insert into tb(身份证号,是否离退休) values('00000000000000001','1010')
insert into tb(身份证号,是否离退休) values('00000000000000002','1010')
insert into tb(身份证号,是否离退休) values('00000000000000003','1010')
insert into tb(身份证号,是否离退休) values('00000000000000004','1010')
insert into tb(身份证号,是否离退休) values('00000000000000005','1010')
insert into tb(身份证号,是否离退休) values('00000000000000006','1010')
insert into tb(身份证号,是否离退休) values('00000000000000007','1010')
insert into tb(身份证号,是否离退休) values('00000000000000008','1010')
insert into tb(身份证号,是否离退休) values('00000000000000009','1010')
insert into tb(身份证号,是否离退休) values('10000000000000000','1000')
insert into tb(身份证号,是否离退休) values('20000000000000000','1000')
go


--生成的临时表px字段，初始值为10，布进值为10
select identity(int,10,10) as px , * into tb1 from tb where 是否离退休 = '1010' order by 身份证号

--生成的临时表px字段，初始值为50，布进值为50
select identity(int,50,50) as px , * into tb2 from tb where 是否离退休 = '1000' order by 身份证号


--50之后插一个51，100之后插一个101，以此类推
select px,身份证号,是否离退休 from
(
select px , 身份证号,是否离退休 from tb1
union all
select px+1 , 身份证号,是否离退休 from tb2
) t
order by px , 身份证号

drop table tb,tb1,tb2

[OracleRoob]

--借用楼上数据

create table tb(身份证号 varchar(18) , 是否离退休 varchar(4))
insert into tb(身份证号,是否离退休) values('00000000000000000','1010')
insert into tb(身份证号,是否离退休) values('00000000000000001','1010')
insert into tb(身份证号,是否离退休) values('00000000000000002','1010')
insert into tb(身份证号,是否离退休) values('00000000000000003','1010')
insert into tb(身份证号,是否离退休) values('00000000000000004','1010')
insert into tb(身份证号,是否离退休) values('00000000000000005','1010')
insert into tb(身份证号,是否离退休) values('00000000000000006','1010')
insert into tb(身份证号,是否离退休) values('00000000000000007','1010')
insert into tb(身份证号,是否离退休) values('00000000000000008','1010')
insert into tb(身份证号,是否离退休) values('00000000000000009','1010')
insert into tb(身份证号,是否离退休) values('10000000000000000','1000')
insert into tb(身份证号,是否离退休) values('20000000000000000','1000')
go


--生成的临时表px字段，初始值为10，布进值为10
select identity(int,10,10) as px , * into tb1 from tb where 是否离退休 = '1010' order by 身份证号

--生成的临时表px字段，初始值为50，布进值为50
select identity(int,50,50) as px , * into tb2 from tb where 是否离退休 = '1000' order by 身份证号


--50之后插一个51，100之后插一个101，以此类推
select px,身份证号,是否离退休 from
(
select px , 身份证号,是否离退休 from tb1
union all
select px+1 , 身份证号,是否离退休 from tb2
) t
order by px , 身份证号

drop table tb,tb1,tb2


/*



px 身份证号 是否离退休
----------- ------------------ -----
10 00000000000000000 1010
20 00000000000000001 1010
30 00000000000000002 1010
40 00000000000000003 1010
50 00000000000000004 1010
51 10000000000000000 1000
60 00000000000000005 1010
70 00000000000000006 1010
80 00000000000000007 1010
90 00000000000000008 1010
100 00000000000000009 1010
101 20000000000000000 1000

*/

[中国风]

create table tb(身份证号 varchar(18) , 是否离退休 varchar(4))
insert into tb(身份证号,是否离退休) values('00000000000000000','1010')
insert into tb(身份证号,是否离退休) values('00000000000000001','1010')
insert into tb(身份证号,是否离退休) values('00000000000000002','1010')
insert into tb(身份证号,是否离退休) values('00000000000000003','1010')
insert into tb(身份证号,是否离退休) values('00000000000000004','1010')
insert into tb(身份证号,是否离退休) values('00000000000000005','1010')
insert into tb(身份证号,是否离退休) values('00000000000000006','1010')
insert into tb(身份证号,是否离退休) values('00000000000000007','1010')
insert into tb(身份证号,是否离退休) values('00000000000000008','1010')
insert into tb(身份证号,是否离退休) values('00000000000000009','1010')
insert into tb(身份证号,是否离退休) values('10000000000000000','1000')
insert into tb(身份证号,是否离退休) values('20000000000000000','1000')
go

select px = identity(int,1,1) , * into tb1 from tb where 是否离退休 = '1010' order by 身份证号
select px = identity(int,1,1) , * into tb2 from tb where 是否离退休 = '1000' order by 身份证号

select *
from
(select * from tb1
union all
select px*5,身份证号,是否离退休 from tb2
)tmp order by px asc,是否离退休 desc

px 身份证号 是否离退休
----------- ------------------ -----
1 00000000000000000 1010
2 00000000000000001 1010
3 00000000000000002 1010
4 00000000000000003 1010
5 00000000000000004 1010
5 10000000000000000 1000
6 00000000000000005 1010
7 00000000000000006 1010
8 00000000000000007 1010
9 00000000000000008 1010
10 00000000000000009 1010
10 20000000000000000 1000

(12 行受影响)