模板函数find这样做为什么有错，该怎么解决！！！！！！！！！！！！

[coldplay968]

struct PERSONINFO
{
int OnLine;
char UserId[10];
bool operator==(const PERSONINFO & rhs)const
{
return ( OnLine == rhs.OnLine && UserId == rhs.UserId);
}
};

PERSONINFO pInfo ;
pInfo.OnLine = 3;
strcpy( pInfo.UserId , "a" );
m_list.push_back(pInfo);

pInfo.OnLine = 4;
strcpy( pInfo.UserId , "b" );
m_list.push_back(pInfo);

pInfo.OnLine = 1;
strcpy( pInfo.UserId , "c" );
m_list.push_back(pInfo);

PERSONINFO Info ;

Info.OnLine = 3;
strcpy( Info.UserId , "a" );

list<PERSONINFO>::iterator it_;
it_ = find(m_list.begin(), m_list.end(), &Info);

报错：d:\microsoft visual studio\vc98\include\algorithm(43) : error C2678: binary '==' : no operator defined which takes a left-hand operand of type 'struct PERSONINFO' (or there is no acceptable conversion)

E:\SortList\SortListDlg.cpp(258) : see reference to function template instantiation 'class std::list<struct PERSONINFO,class std::allocator<struct PERSONINFO> >::iterator __cdecl std::find(class std::list<struct PERSONINFO,class std::allocat
or<struct PERSONINFO> >::iterator,class std::list<struct PERSONINFO,class std::allocator<struct PERSONINFO> >::iterator,struct PERSONINFO *const & )' being compiled

[taodm]

it_ = find(m_list.begin(), m_list.end(), Info);

[taodm]

你这个也蛮强的UserId == rhs.UserId
一个strcmp

[coldplay968]

bool operator ==(const PERSONINFO & rhs)const
{

return ( OnLine == rhs.OnLine && strcmp( UserId ,rhs.UserId) );
}
改成了这样还是报错啊

[珍惜生命远离CPP]

return ( OnLine == rhs.OnLine && (0==strcmp( UserId ,rhs.UserId)) );

[coldplay968]

用了楼上的还是报错

[taodm]

it_ = find(m_list.begin(), m_list.end(), Info);

[qingcairousi]

编译器说得很清楚了，需要的是二元的operator==,把operator==要么独立出来做成友元，要么做成静态的试试

[qingcairousi]

另外find的调用也错了，最后一个参数不应该传地址，应该传对象

[coldplay968]

bool operator ==(const PERSONINFO & rhs)const
{
return ( OnLine == rhs.OnLine && (0==strcmp( UserId ,rhs.UserId) ) );
}

PERSONINFO pInfo ;
pInfo.OnLine = 3;
strcpy( pInfo.UserId , "a" );
m_list.push_back(pInfo);

pInfo.OnLine = 4;
strcpy( pInfo.UserId , "b" );
m_list.push_back(pInfo);

pInfo.OnLine = 1;
strcpy( pInfo.UserId , "c" );
m_list.push_back(pInfo);

PERSONINFO Info ;

Info.OnLine = 3;
strcpy( Info.UserId , "a" );

list<PERSONINFO>::iterator it_;
it_ = find(m_list.begin(), m_list.end(), Info);

int i =(*it).OnLine;
char str[10];
strcpy( str, (*it).UserId );

改成这个样子就不报错了，但是 里面的值就不对了，明明就有
Info.OnLine = 3;
strcpy( Info.UserId , "a" ); 这个东西啊
晕死

[coldplay968]

int i =(*it_).OnLine;
char str[10];
strcpy( str, (*it_).UserId );

知道哪里错了 是(*it_) 少了个 “_”
郁闷，搞了半天，谢谢大家了