求一字符串中子串逆转输出的算法！

[kyh1234567]

现有一字符串 str = "I am a student!";
要求输出的结果为: student a am I

现求一算法来实现此功能，在线等，多谢~

[zxfishhack]

str是什么类型的呀

[珍惜生命远离CPP]

#include<vector>
#include<string>
#include<iostream>
#include<algorithm>
#include<iterator>
#include<sstream>
using namespace std;



int main(int argc, char* argv[])
{
stringstream str;
str<<"I am a student";
vector<string> v;
string xx;
while(str>>xx)
v.push_back(xx);
copy(v.rbegin(),v.rend(),ostream_iterator<string>(cout," "));
return 0;
}

[merlinfang]

还要去除标点符号吗?

[qhfu]

一个不错的算法,, 先逆转整个字符串,再分别逆转每个单词

[zxfishhack]

为什么我的输出结果是
student a am I

[HewpKanXue]

参考了一下二楼的成果，改了一下：
stringstream str;
str<<"I am a student";
list<string> Ls;
copy(istream_iterator<string>(str),istream_iterator<string>(),front_inserter(Ls));
copy(Ls.begin(),Ls.end(),ostream_iterator<string>(cout," "));

[suyouxin]

如果只是输出
#include <stdio.h>
#include <string.h>

int main(void)
{
char str[20] = {0};
int n;

strxfrm(str, "I am a student", sizeof(str));

n = strlen(str);
while(n--)
{
if (str[n] == ' ')
{
str[n] = '\0';
printf("%s ", str + n + 1);
}
}
printf(str);

return 0;
}

[zxfishhack]

没看清问题。。。收回我的回复

[kyh1234567]

问题已经解决，多谢楼上各位兄弟！

[Braint_Yuan]

void strReverse(char* str,char *strRes)
{
char *stack[Max];
char *tem;
int index = 0;
int m = 0;
// 分离出每个单词，并在不是第一个单词的末尾加上空格
for(int i = 0;i <=strlen(str);i++)
{
if(str[i] == ' ' || str[i] == '\0')
{

if(index == 0)
{
// 新申请一块内存用于保存分离出的单词
tem = new char[i - index +1];
strncpy(tem,str+index,i-index);
// 在末尾加上结束符，注意此结束符号的序号
tem[i-index] = '\0';
}
else
{
tem = new char[i - index + 1];
strncpy(tem,str+index+1,i-index - 1);
tem[i-index-1] = ' ';
tem[i-index] = '\0';
}
index = i;
stack[m] = tem;
m++;
}

}
strcpy(strRes,stack[m-1]);
// 释放申请的内存
delete stack[m-1];
for(int j = m-2;j>=0;j--)
{
strcat(strRes,stack[j]);
delete stack[j];
}


}
int main()
{

char *str = "I am a student";
char ret[50];
strReverse(str,ret);
cout<<ret<<endl;
system("pause");
return 0;
}