并非所有的代码路径都返回值

[gegeblue]

public DateTime UpdateAndInsert(Guid OverTimeHeadId, int OverTimeStatusId, Guid UserId,DateTime CreateTimeId,Guid guidId)
{
using (TransactionScope ts = new TransactionScope())//两个一起执行
{
string strSql = "UPDATE OverTimeHead SET OverTimeStatusId = '{1}' WHERE (OverTimeHeadId = '{0}')";

new CommonData().ExeNonQuery(strSql);

strSql = "INSERT INTO OverTimeFlows ( UserId, OverTimeStatusId,OverTimeFlowsId,CreateDateTime) VALUES ('{2}','{1}','{4}','{3}')";


new CommonData().ExeNonQuery(strSql);

ts.Complete();
}
}

[lovvver]

你要问的是什么

[dengenming]

你声明的类命是要返回一个DateTime 啊


return ...

[xray2005]

都没有return一个值呢!

[gegeblue]

二楼：问错在哪里啊!
三楼：我是要insert和update，我return什么啊？

[kimiya25]

你不要return 什么..干吗构造方法时声明了返回值..去掉..改void不就好了?

[gegeblue]

在调试，成功了给你们加分

[lovvver]

public void UpdateAndInsert(Guid OverTimeHeadId, int OverTimeStatusId, Guid UserId,DateTime CreateTimeId,Guid guidId)
{
using (TransactionScope ts = new TransactionScope())//两个一起执行
{
string strSql = "UPDATE OverTimeHead SET OverTimeStatusId = '{1}' WHERE (OverTimeHeadId = '{0}')";

new CommonData().ExeNonQuery(strSql);

strSql = "INSERT INTO OverTimeFlows ( UserId, OverTimeStatusId,OverTimeFlowsId,CreateDateTime) VALUES ('{2}','{1}','{4}','{3}')";


new CommonData().ExeNonQuery(strSql);

ts.Complete();
}
}

[guojh021]

public DateTime UpdateAndInsert

这个函数要示有返回值 DateTime

这样声明就可以无返回值了：public void UpdateAndInsert

[chenyuling]

public DateTime UpdateAndInsert(Guid OverTimeHeadId, int OverTimeStatusId, Guid UserId,DateTime CreateTimeId,Guid guidId)
改成
public void UpdateAndInsert(Guid OverTimeHeadId, int OverTimeStatusId, Guid UserId,DateTime CreateTimeId,Guid guidId)