XMLHttpRequest对象send方法服务器端取不到的问题

[Heqikun]

function send_Request()
{
var http_request = new ActiveXObject("Microsoft.XMLHTTP");
http_request.open("POST","/AJAXExample/process.jsp",true);
http_request.send("num1=10&num2=23");
}
这段代码发到服务器端,没能用request.getParameter("num1");方法取到num1,num2参数值,请各位高手赐教

[Heqikun]

AJAX中的XMLHttpRequest对象的问题

[vagrant1984]

post提交的时候send方法使用错误

[Heqikun]

该怎么提交?

[Heqikun]

send方法该怎么用?

[小伟]

上面的问题解决了没?
我想说一下就是如果你是POST提交的话最好要设置一下
XMLHttpRequest对象的请求头
var http_request = new ActiveXObject("Microsoft.XMLHTTP");
http_request.open("POST","/AJAXExample/process.jsp",true);
http_request.setRequestHeader("Content-Type', 'application/x-www-form-urlencoded');
http_request.send("num1=10&num2=23");
这样我想就应该可以得到了

[IhaveGotYou]

给个例子:
function createXMLHttpRequest(){
if (window.ActiveXObject){
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
else if(window.XMLHttpRequest){
xmlHttp = new XMLHttpRequest();
}
}

function sendRequest(pageIndex){
createXMLHttpRequest();
//处理方法
var url;
var index=pageIndex-1;
var xml=document.getElementById("textarea" + pageIndex).value;
currPageIndex=pageIndex;
url=uris[index]+"?transType="+transtypes[index]+"&transMessage="+xml+"×tamp="+ new Date().getTime();
xmlHttp.open("POST",url,true);
xmlHttp.onreadystatechange = handleStateChange;
xmlHttp.send();
}

//回调方法
function handleStateChange(){
if (xmlHttp.readyState == 4){
if (xmlHttp.status == 200){
//返回结果
document.getElementById("textarea"+currPageIndex+currPageIndex).value=xmlHttp.responseText;
}
}
}

[IhaveGotYou]

全局变量:
tabCount = 7;
var xmlHttp;
var currPageIndex;
var uris=["tc1.do","tc2.do","tc3.do","tc4.do","tc5.do","tc6.do","tc7.do"];
var transtypes=[101,102,103,104,105,106,107];