发现：d2006的inline不是很可靠

今天做一个函数发现一些怪事，通过调试发现，delphi2006的inline新语法在特定情况下会出现错误。我做了个测试程序，不知道有没有搞错，大家鉴定鉴定，如果真的有问题，大家以后使用时要小心哟

///////////////////////////
// project
///////////////////////////

program inline_err;

{$APPTYPE CONSOLE}

uses
SysUtils,
other_unit in 'other_unit.pas';

procedure normal(var k: my_type; delta_x, delta_y: integer);
//没有inline的函数
begin
inc(k.x1, delta_x);
inc(k.x2, delta_x);

inc(k.y1, delta_y);
inc(k.y2, delta_y);
end;

procedure compare(normal_r, inlined_r: my_type);
//比较结果
begin
if (normal_r.x1 <> inlined_r.x1)
or (normal_r.x2 <> inlined_r.x2)
or (normal_r.y1 <> inlined_r.y1)
or (normal_r.y2 <> inlined_r.y2) then
writeln('Error')
else
writeln('Ok');
end;

procedure test_failed();
var
source, normal_r, inlined_r: my_type;
begin
source.x1 := 10;
source.x2 := 20;
source.y1 := 10;
source.y2 := 20;

normal_r := source;
inlined_r := source;

normal(normal_r, -normal_r.x1, -normal_r.y1);
inlined(inlined_r, -inlined_r.x1, -inlined_r.y1);

compare(normal_r, inlined_r);
end;

procedure test_failed2();
var
source, normal_r, inlined_r: my_type;
begin
source.x1 := 10;
source.x2 := 20;
source.y1 := 10;
source.y2 := 20;

normal_r := source;
inlined_r := source;

normal(normal_r, -normal_r.x1, -normal_r.y1);
inlined2(inlined_r, -inlined_r.x1, -inlined_r.y1);

compare(normal_r, inlined_r);
end;

procedure test_success();
var
source, normal_r, inlined_r: my_type;
begin
source.x1 := 10;
source.x2 := 20;
source.y1 := 10;
source.y2 := 20;

normal_r := source;
inlined_r := source;

normal(normal_r, -normal_r.x2, -normal_r.y2);
inlined(inlined_r, -inlined_r.x2, -inlined_r.y2);

compare(normal_r, inlined_r);
end;



var
s: string;
begin
{ TODO -oUser -cConsole Main : Insert code here }
test_failed();
test_failed2();
test_success();

writeln('press ENTRY to continue..');
readln(s);
end.


/////////////////////////////
/// other unit
/////////////////////////////
unit other_unit;

interface
uses
SysUtils, Types;

type
my_type = record //or object
x1, y1, x2, y2: integer;
end;

procedure inlined(var k: my_type; delta_x, delta_y: integer); inline;
procedure inlined2(var k: my_type; delta_x, delta_y: integer); inline;

implementation

procedure inlined(var k: my_type; delta_x, delta_y: integer);
begin
inc(k.x1, delta_x);
inc(k.x2, delta_x);

inc(k.y1, delta_y);
inc(k.y2, delta_y);
end;

procedure inlined2(var k: my_type; delta_x, delta_y: integer);
begin
k.x1 := k.x1 + delta_x;
k.x2 := k.x2 + delta_x;

k.y1 := k.y1 + delta_y;
k.y2 := k.y2 + delta_y;
end;


end.

运行可以发现，inline版的函数没有正确被编译，产生这种情况的条件：
1. inline函数在别的单元
2. 调用时，k.x1,k.y1作为delta_x, delta_y的实际参数