xml不能用xsl显示样式的问题``我都要哭了!
在ie中只能显示有标签的xml 为什么啊!!!!
xml源文件:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE employees SYSTEM "employee.dtd">
<?xml-stylesheet type="text/xsl" herf="employee.xslt"?>
<employees>
<employee>
<employeeID>1001</employeeID>
<name>kemo</name>
<job>软件工程师</job>
<tel>1300000000</tel>
<mail>kemo@12.com</mail>
</employee>
<employee>
<employeeID>1002</employeeID>
<name>tom</name>
<job>软件测试师</job>
<tel>1300000000</tel>
<mail>kemo@12.com</mail>
</employee>
<employee>
<employeeID>1003</employeeID>
<name>susan</name>
<job>软件构架师</job>
<tel>1300000000</tel>
<mail>kemo@12.com</mail>
</employee>
<employee>
<employeeID>1004</employeeID>
<name>juck</name>
<job>软件测试师</job>
<tel>1300000000</tel>
<mail>kemo@12.com</mail>
</employee>
</employees>
--------------------------------------
dtd源文件:
<?xml version="1.0" encoding="UTF-8"?>
<!ELEMENT employees (employee+)>
<!ELEMENT employee (employeeID, name, job, tel, mail)>
<!ELEMENT employeeID (#PCDATA)>
<!ELEMENT name (#PCDATA)>
<!ELEMENT job (#PCDATA)>
<!ELEMENT tel (#PCDATA)>
<!ELEMENT mail (#PCDATA)>
--------------------------------------
xsl源文件:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="employees">
<html>
<head>
<title></title>
</head>
<body>1111</body>
</html>
</xsl:template>
</xsl:stylesheet>