why is 21 + 31 equal to 5?

fishmen26 2007-07-02 04:44:06

printf("why is 21 + 31 equal to %d?\n",21 + 31);

在一台 int 类型长度为4字节的机器上,下面是它的答应结果:

why is 21 + 31 equal 5?

请问为什么?基本原理是什么?

这是 a book on c ,第3章习题7

我在TUBBOC 上 INT 2字节运行结果 21+31=52

将编译器换成 VC 运行 INT 4字节运行结果仍然是 21+31=52

搞不懂了,上来问问

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zgg___ 2007-07-06

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不光少了个2，前面还少了个to。

debug1984 2007-07-05

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不管2字节还是4字节,52是装得下的.
如果那章将的不是long和int等而是讲printf的话,那就是印刷错误.
如果是技巧性的,就可以多研究下是l 还是 1

fire_woods 2007-07-03

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1和l很像

fishmen26 2007-07-03

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能不能说清楚点,谢谢

adrian8181 2007-07-02

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是长整形2加长整形3

fishmen26 2007-07-02

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那样 2字节和 4字节之间有区别吗?

songzhenqiu 2007-07-02

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我猜那属本意是2“l”+3“l”

fishmen26 2007-07-02

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书是学校借的,不应该是盗版哦

原帖: http://stackoverflow.com/questions/1863153/why-unsigned-int-0xffffffff-is-equal-to-int-1 =======================================================================================================...

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