hibernate中Criteria能多表查询吗?

[liou825]

如题.如果能,请贴下相关的简单代码..........

[dreamover]

Criteria criteria = session.createCriteria(User.class);

criteria.createCriteria("department","d").list();

[yw4821182_101]

List result = session.createCriteria(obj1.getClass())
.add(Example.create(obj1))
.createCriteria(obj2.getClass())
.add(Example.create(obj2))
.list()
你可以试下

[dreamover]

Cretiria里有

createCretiria(Class clazz)这样的方法么？

[kidfang]

ls的还是单表啊？！

[dreamover]

把你的需求说清楚一些，hbm及相关代码列出来

[yw4821182_101]

不好意思搞错了饿

List result = session.createCriteria(Cat.class)
.add(Example.create(cat))
.createCriteria("mate")
.add(Example.create(cat.getMate()))
.list()
一般对关联对象

[kidfang]

好东西，收了!

[SDMRauquin]

DetachedCriteria dc = DetachedCriteria.forClass(TExpert.class);
dc.addOrder(Order.desc("expertid"));
dc.createAlias("extype","b");
dc.add(Property.forName("b.extypeid").eq(new Long(expertForm.getExtypeId())));
dc.add(Property.forName("name").like(expertForm.getSearchName(),MatchMode.ANYWHERE));
dc.add(Property.forName("keyword").like(expertForm.getSearchName(),MatchMode.ANYWHERE));
}

[liou825]

好久没人回,我想别的办法解决了.
不过在这还是要多谢各位.....结贴