研究一下这个代码，为什么得到这么奇怪的结果！！！

[zzyjsjcom]

#include <iostream>
using namespace std;

class B
{
public:
B() {cout << "B::B() " << endl;}
void f() {cout << "B:f() " << endl;}
private:

};

class D
{
public:
D(){cout << "D::D()" << endl;}
void f() { void B::f(); }
private:

};

int main()
{
D d;
d.f();
return 0;
}

[jixingzhong]

class D
{
public:
D(){cout << "D::D()" << endl;}
void f() { B b; b.f(); }
private:

};

[jixingzhong]

void f() { void B::f(); } //这个算什么？ 声明？ 调用？

void f() { B b; b.f(); } //由于方法不是静态的，只有实例化对象后调用

[skywing918]

结果是什么没发上来啊?

[jixingzhong]

class B
{
public:
B() {cout << "B::B() " << endl;}
static void f() {cout << "B:f() " << endl;} //定义 static 方法
private:

};

class D
{
public:
D(){cout << "D::D()" << endl;}
void f() { B::f(); } //OK， 注意不要前面的 返回类型
private:

};

[yangar9179]

#include <iostream>
using namespace std;

class B
{
public:
B() {cout << "B::B() " << endl;}
void f() {cout << "B:f() " << endl;}
private:

};

class D
{
public:
D(){cout << "D::D()" << endl;}
void f() { B b;b.f(); }
private:

};

int main()
{
D d;
d.f();
getchar();
return 0;
}

[zzyjsjcom]

谢谢