21,886
社区成员
发帖
与我相关
我的任务
分享在ajax中用POST方法提交的XML串，服务器端如何回显到客户端？
符上原代码：
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<META NAME="Generator" CONTENT="EditPlus">
<META NAME="Author" CONTENT="">
<META NAME="Keywords" CONTENT="">
<META NAME="Description" CONTENT="">
</HEAD>
<script>
var xmlhttp;
function createXmlRequest(){
if(window.ActiveXObject){
xmlhttp=new window.ActiveXObject("Microsoft.XMLHTTP");
}else{
if(window.XMLHttpRequest){
xmlhttp=new XMLHttpRequest();
}else{
alert("error");
}
}
var url="postxml.php?"+new Date().getTime();
xmlhttp.open("POST",url,true);
xmlhttp.setRequestHeader("Content-Type","application/x-www-form-urlencoded;");
xmlhttp.onreadystatechange=show;
xmlhttp.send(createXml());
}
function createXml(){
var xml="<pets>";
var options=document.getElementById("petTypes").childNodes;
var option=null;
for(var i=0;i<options.length;i++){
option=options[i];
if(option.selected){
xml=xml+"<type>"+option.value+"</type>";
}
}
alert(xml+"</pets>");
return xml+"</pets>";
}
function show(){
if(xmlhttp.readyState==4){
if(xmlhttp.status==200){
var response=document.getElementById("response");
if(response.hasChildNodes()){
response.removeChild(response.childNodes[0]);
}
document.getElementById("response").appendChild(document.createTextNode(xmlhttp.responseText));
}
}
}
</script>
<BODY>
<h1>select OPtion</h1>
<form action="#">
<select name="s" id="petTypes" multiple >
<option value="a">afds</option>
<option value="子子子">子子子</option>
<option value="ccc">cccc</option>
<option value="声东击西test">声东击西test</option>
</select>
<input type="button" value="XMLPOST" onclick="createXmlRequest();">
</form>
Server response
<div id="response">test</div>
</BODY>
</HTML>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<META NAME="Generator" CONTENT="EditPlus">
<META NAME="Author" CONTENT="">
<META NAME="Keywords" CONTENT="">
<META NAME="Description" CONTENT="">
</HEAD>
<script>
var xmlhttp;
function createXmlRequest(){
if(window.ActiveXObject){
xmlhttp=new window.ActiveXObject("Microsoft.XMLHTTP");
}else{
if(window.XMLHttpRequest){
xmlhttp=new XMLHttpRequest();
}else{
alert("error");
}
}
var url="postxml.php?"+new Date().getTime();
xmlhttp.open("POST",url,true);
xmlhttp.setRequestHeader("Content-Type","application/x-www-form-urlencoded;");
xmlhttp.onreadystatechange=show;
xmlhttp.send(createXml());
}
function createXml(){
var xml="<pets>";
var options=document.getElementById("petTypes").childNodes;
var option=null;
for(var i=0;i<options.length;i++){
option=options[i];
if(option.selected){
xml=xml+"<type>"+option.value+"</type>";
}
}
alert(xml+"</pets>");
return xml+"</pets>";
}
function show(){
if(xmlhttp.readyState==4){
if(xmlhttp.status==200){
var response=document.getElementById("response");
if(response.hasChildNodes()){
response.removeChild(response.childNodes[0]);
}
document.getElementById("response").appendChild(document.createTextNode(xmlhttp.responseText));
}
}
}
</script>
<BODY>
<h1>select OPtion</h1>
<form action="#">
<select name="s" id="petTypes" multiple >
<option value="a">afds</option>
<option value="子子子">子子子</option>
<option value="ccc">cccc</option>
<option value="声东击西test">声东击西test</option>
</select>
<input type="button" value="XMLPOST" onclick="createXmlRequest();">
</form>
Server response
<div id="response">test</div>
</BODY>
</HTML>
...全文
请发表友善的回复…
发表回复
hij333 2007-08-02
- 打赏
- 举报
客户端:下面这个函数里面应该添加接收后的处理.
function show(){
if(xmlhttp.readyState==4){
if(xmlhttp.status==200){
var return_value = xmlhttp.responseXML;
//然后你再对返回的这个值进行处理.
}
}
服务器端:postxml.php中
根据你所获取的参数进行输出一个XML格式的东西.
我也是刚接触.如有不对,敬请谅解.
function show(){
if(xmlhttp.readyState==4){
if(xmlhttp.status==200){
var return_value = xmlhttp.responseXML;
//然后你再对返回的这个值进行处理.
}
}
服务器端:postxml.php中
根据你所获取的参数进行输出一个XML格式的东西.
我也是刚接触.如有不对,敬请谅解.
