急!!国防科大自考汇编实验题目解决方法(完成填空)

[PZL99COM]

;*********************************************************************
;实验题目:制作电子钟
;原理:利用定时器产生的中断信号作为时钟计数值,制作一个电子钟,(XX分XX秒)
;要求:(1)看懂参考程序的流程,理解关键语句部分的作用.
; (2)参考程序中没有保存和恢复中断向量的入口值,程序退出后,系统死机,
; 请在适当位置添加相应语句,保证程序退出后,系统正常,保存中断向量
; 入口值语句位置已指出,恢复部分请自己确定适当位置.
;*********************************************************************


data segment para public'data'
count100 db 100
tenmin db 0
minute db 0
db':'
tensec db 0
second db 0
data ends

stack segment para stack'stack'
db 256 dup(?)
stack ends

code segment para public'code'

start proc far
assume cs:code

push ds
sub ax,ax
push ax

mov ax,data
mov es,ax
assume es:data
mov si,82h
mov di,offset tenmin
mov cx,5
cld
rep movsb ;取命令行参数

mov ds,ax
assume ds:data

mov ah,0
mov al,1
int 10h

mov ah,2
mov dh,10
mov dl,20
int 10h

mov ah,9
mov al,' '
mov bl,2eh
mov cx,5
int 10h

mov ah,2
mov dh,10
mov dl,20
int 10h

mov ah,0
int 16h

cli
;************************************
;在此处完成填空,保存中断向量入口值,
;并且接管中断处理
;************************************





sti

cli
mov al,36h
out 43h,al
mov bx,11932
mov al,bl
out 40h,al
mov al,bh
out 40h,al
mov al,bh
out 40h,al
mov al,0bch
out 21h,al
sti ;初始化定时器8253

forever: mov ah,2
mov dh,10
mov dl,20
int 10h
mov bx,offset tenmin
mov cx,5
dispclk: mov al,[bx]
call dispchar
inc bx
loop dispclk
mov al,second
waitl: cmp al,second
jz waitl
mov ah,1
int 16h
jnz ppp
mov al,7
mov ah,14
int 10h
jmp forever
ppp: jmp rrr

timer proc far
push ax
dec count100
jnz timerx
mov count100,100
inc second
cmp second,'9'
jle timerx
mov second,'0'
inc tensec
cmp tensec,'6'
jl timerx
mov tensec,'0'
inc minute
cmp minute,'9'
jle timerx
mov minute,'0'
inc tenmin
cmp tenmin,'6'
jl timerx
mov tenmin,'0'
timerx: mov al,20h
out 20h,al
pop ax
iret
timer endp ;中断处理程序

dispchar proc near
push bx
mov bx,0
mov ah,14
int 10h
pop bx
ret
dispchar endp ;字符显示过程

rrr: ret
start endp

code ends
end start

;此源代码我编译连接成功,但时钟没起作用.

[ReverseEngineering]

完了，这几天看A片汇编忘光了

[puppy52020]

完了，这几天看A片汇编忘光了

真逗。。帮你顶~~~

[paullbm]

mov al,second
waitl: cmp al,second
jz waitl


子程序forever中的这几句岂不是造成了死循环？？

[zara]

是 jz 指令, 不是 jmp 指令, 不会形成死循环的吧.

[paullbm]

mov al,second
waitl: cmp al,second
jz waitl


假设second=5，那al也等于5，两个相同的数进行比较，当然符合jz(等于0则跳转)的条件了！
al是用原始数second赋值的，但仍和这个原始数进行比较，当然是只可能相等了！！

[zara]

可是, 按照题目的要求, 应该有实时时钟中断 timer 来对 second 进行修改的啊

[日立奔腾浪潮微软松下联想]

data segment para public 'data'
count100 db 100
tenmin db '0'
minute db '0'
db ':'
tensec db '0'
second db '0'
int08save dd 0
data ends

stack segment para stack 'stack'
db 256 dup(0)
stack ends

code segment para public 'code'

start proc far
assume cs:code, ds:data, ss:stack

push ds
sub ax,ax
push ax

mov ax,data
mov ds,ax

mov ah,0
mov al,1
int 10h

mov ah,2
mov dh,10
mov dl,20
int 10h

mov ah,9
mov al,' '
mov bx,002eh
mov cx,5
int 10h

mov ah,2
mov dh,10
mov dl,20
int 10h

;mov ah,0
;int 16h

cli
;************************************
;在此处完成填空,保存中断向量入口值,
;并且接管中断处理
;************************************
mov ax,3508h
int 21h
mov word ptr int08save,bx
mov word ptr int08save+2,es
push ds
mov ax,2508h
push cs
pop ds
lea dx,timer
int 21h
pop ds
sti

cli
mov al,36h
out 43h,al
mov bx,11932
mov al,bl
out 40h,al
mov al,bh
out 40h,al
mov al,bh
out 40h,al
mov al,0bch
out 21h,al
sti ;初始化定时器8253

forever:
mov ah,2
mov dh,10
mov dl,20
int 10h
mov bx,offset tenmin
mov cx,5
dispclk:
mov al,[bx]
call dispchar
inc bx
loop dispclk
mov al,second
waitl:
cmp al,second
jz waitl
mov ah,1
int 16h
jnz ppp
mov al,7
mov ah,14
int 10h
jmp forever
ppp:
jmp rrr

timer proc far
push ds
push ax
mov ax,data
mov ds,ax
pushf
call dword ptr [int08save]
dec count100
jnz timerx
mov count100,100
inc second
cmp second,'9'
jle timerx
mov second,'0'
inc tensec
cmp tensec,'6'
jl timerx
mov tensec,'0'
inc minute
cmp minute,'9'
jle timerx
mov minute,'0'
inc tenmin
cmp tenmin,'6'
jl timerx
mov tenmin,'0'
timerx:
mov al,20h
out 20h,al
pop ax
pop ds
iret
timer endp ;中断处理程序

dispchar proc near
push bx
mov bx,0
mov ah,14
int 10h
pop bx
ret
dispchar endp ;字符显示过程

rrr: ; 如果要求结束后系统死机，下面7行注释掉即可
mov ax,2508h
lds dx,int08save
int 21h
mov ax,3
int 10h
mov ax,4c00h
int 21h
ret
start endp

code ends
end start

[heavenscloud]

哦牙~~X86汇编忘记的差不多鸟