救命

[cghhhh]

各位高手帮忙看看。
有两数组如下：
userid[]={C-CS0042，C-CS0043，C-CS0046，C-WZ0001，C-WZ0002，C-WZ0003，C-WZ0004，C-WZ0005，C-WZ0006，C-WZ0007，C-WZ0008，C-WZ0009}
customerid[]={C-WZ0001，C-WZ0001，C-WZ0003，C-WZ0003，C-WZ0003，C-WZ0004，C-WZ0004，C-WZ0004，C-WZ0005，C-WZ0005，C-WZ0005，C-WZ0006，C-WZ0006，C-WZ0006，C-WZ0007，C-WZ0007，C-WZ0007，C-WZ0008，C-WZ0008，C-WZ0008，C-WZ0009，C-WZ0009，C-WZ0009，C-CS0042，C-CS0042，C-WZ0002，C-WZ0002，C-WZ0002，C-CS0046，C-CS0046，C-CS0043，C-CS0043}
把userid[]中响分别和customerid[]中的项进行比较，记录userid[]中的每一项对应着customerid[]的多少。即得到row[]={2,3,3,3,3,3,3,3,2,3,2,2}

[anny_nmh]

你是问实现过程吗？两个for循环就搞定了呀

[cghhhh]

对要的就是实现过程

[fengyupeng]

嵌套 循环

[qianwu1984]

customerid[]中的成員重復如何顯示row[]？例如：
customerid[]={C-WZ0001，C-WZ0001}
userid[]={C-WZ0001}
row[]里的值是什么？？

[cghhhh]

row[]里的值是customerid[]与customerid[]比较所得。
例如customerid中有2个C-CS0042，则row[]的值为2。

[dd379980649]

哈哈哈 我还没看明白Hashcode,,应该用Hashcode可以比较简单的解决吧!
所以我把你那连个数组变成String类型的了~~哈哈~~比较复杂吧,
//:ArraysSort.java
public class ArraysSort{
public static void main(String[] args){
String userid[]={"C-CS0042","C-CS0043","C-CS0046","C-WZ0001","C-WZ0002",
"C-WZ0003","C-WZ0004","C-WZ0005","C-WZ0006","C-WZ0007","C-WZ0008","C-WZ0009"};
String customerid[]={"C-WZ0001","C-WZ0001","C-WZ0003","C-WZ0003","C-WZ0003",
"C-WZ0004","C-WZ0004","C-WZ0004","C-WZ0005","C-WZ0005","C-WZ0005","C-WZ0006","C-WZ0006",
"C-WZ0006","C-WZ0007","C-WZ0007","C-WZ0007","C-WZ0008","C-WZ0008","C-WZ0008","C-WZ0009",
"C-WZ0009","C-WZ0009","C-CS0042","C-CS0042","C-WZ0002","C-WZ0002","C-WZ0002","C-CS0046",
"C-CS0046","C-CS0043","C-CS0043"};
MySort ms=new MySort(userid,customerid);
ms.ptl();
}
}

class MySort{
private String[] a;
private String[] b;
private int[] row;
private int mun;
MySort(String[] a,String[] b){
this.a=a;
this.b=b;
this.row=new int[a.length];
}
private void sort(){
for(int i=0;i<a.length;i++){
mun=0;
for(int j=0;j<b.length;j++){
if(a[i].equals(b[j])){
mun++;
}
}
row[i]=mun;
}
}
void ptl(){
sort();
for(int k=0;k<row.length;k++){
System.out.print(row[k]+" ");
}
}

}