Ajax问题！

[zhangdong572]

网上的ajax的例子都是 返回一个字符串 太简单
怎样用response返回一个xml文件 然后客户端用js解析？？

[zhangdong572]

不会吧 怎么没人关注！我自己顶！

[pvdpcelb]

<script language="javascript">
var http_request = false;
function send_request(url) {//初始化、指定处理函数、发送请求的函数
http_request = false;
//开始初始化XMLHttpRequest对象
if(window.XMLHttpRequest) { //Mozilla 浏览器
http_request = new XMLHttpRequest();
if (http_request.overrideMimeType) {//设置MiME类别
http_request.overrideMimeType('text/xml');
}
}
else if (window.ActiveXObject) { // IE浏览器
try {
http_request = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
http_request = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {}
}
}
if (!http_request) { // 异常，创建对象实例失败
window.alert("不能创建XMLHttpRequest对象实例.");
return false;
}
http_request.onreadystatechange = processRequest;
// 确定发送请求的方式和URL以及是否同步执行下段代码
http_request.open("GET", url, true);
http_request.send(null);
}
// 处理返回信息的函数
function processRequest() {
if (http_request.readyState == 4) { // 判断对象状态
if (http_request.status == 200) { // 信息已经成功返回，开始处理信息
var returnObj = http_request.responseXML;
var xmlobj = http_request.responseXML;
var employees = xmlobj.getElementsByTagName("employee");
var feedbackStr = "";
for(var i=0;i<employees.length;i++) { // 循环读取employees.xml的内容
var employee = employees[i];
feedbackStr += "员工：" + employee.getAttribute("name");
feedbackStr += " 职位：" + employee.getElementsByTagName("job")[0].firstChild.data;
feedbackStr += " 工资：" + employee.getElementsByTagName("salary")[0].firstChild.data;
feedbackStr += "\r\n";
}
alert(feedbackStr);
} else { //页面不正常
alert("您所请求的页面有异常。");
}
}
}
</script>

[pvdpcelb]

<input type="button" name="read" value="读取XML" onClick="send_request('employees.xml')">

employees.xml

<?xml version="1.0" encoding="gb2312"?>
<employees>
<employee name="J.Doe">
<job>Programmer</job>
<salary>32768</salary>
</employee>
<employee name="A.Baker">
<job>Sales</job>
<salary>70000</salary>
</employee>
<employee name="Big Cheese">
<job>CEO</job>
<salary>100000</salary>
</employee>
</employees>