如何根据的选择改变button的value和enable?? <HTML>
<HEAD>
<TITLE> New Document </TITLE>
</HEAD>
<script>
function checkon()
{
if (document.ss1.select1.value="B")
{
document.ss1.button3.value="hhhh";
document.ss1.button1.enabled=false;
document.ss1.button2.enabled=false;
}
else if (document.ss1.select1.value="A")
{
document.ss1.button3.value="oooo";
document.ss1.button1.enabled=true;
document.ss1.button2.enabled=true;
}
else if (document.ss1.select1.value="C")
{
document.ss1.button3.value="pppp";
document.ss1.button1.enabled=true;
document.ss1.button2.enabled=true;
}
}
</script>
<BODY>
<form name=ss1>
<select name="select1" onChange="checkon()">
<option value="A">button1</option>
<option value="B">button2</option>
<option value="C">button3</option>
</select>
<input type="submit" name="button1" value="Aaaa">
<input type="submit" name="button2" value="Bbbb">
<input type="submit" name="button3" value="Cccc">
</form>
</BODY>
</HTML>
上面这段代码不按照我想做的。例如选择button2的时候,为什么按钮enable不能为false?