求救 关于 mod 的正确使用!!!

[jsg]

[Chxis]

是fmod吗?

[smartboyme]

我猜是吧！
fmod
Calculates the floating-point remainder.

double fmod( double x, double y );

Function Required Header Compatibility
fmod <math.h> ANSI, Win 95, Win NT


For additional compatibility information, see Compatibility in the Introduction.

Libraries

LIBC.LIB Single thread static library, retail version
LIBCMT.LIB Multithread static library, retail version
MSVCRT.LIB Import library for MSVCRT.DLL, retail version


Return Value

fmod returns the floating-point remainder of x / y. If the value of y is 0.0, fmod returns a quiet NaN. For information about representation of a quiet NaN by the printf family, see printf.

Parameters

x, y

Floating-point values

Remarks

The fmod function calculates the floating-point remainder f of x / y such that x = i * y + f, where i is an integer, f has the same sign as x, and the absolute value of f is less than the absolute value of y.

Example

/* FMOD.C: This program displays a
* floating-point remainder.
*/

#include <math.h>
#include <stdio.h>

void main( void )
{
double w = -10.0, x = 3.0, y = 0.0, z;

z = fmod( x, y );
printf( "The remainder of %.2f / %.2f is %f\n", w, x, z );
printf( "The remainder of %.2f / %.2f is %f\n", x, y, z );

}


Output

The remainder of -10.00 / 3.00 is -1.000000

[Chxis]

z=fmod(x,y)
x对y取模,并付给z,

to smartboyme(小东):
double w = -10.0, x = 3.0, y = 0.0, z;

z = fmod( x, y );

but y==0.0 ?????
z will be 0 ,

[smartboyme]

错了，
应该是：
double x = 3.0, y = -10.0, z;
我真是太粗心了！

msdn也有错啊！

[smartboyme]

还是错
double x = -10.0，y=3.0, z;

灌水灌多了。

CSDN怎么没有Undo啊！
我想undo一下！

[Chxis]

haha,我也赞成undo

[SSTS]

CTRL+U

[SSTS]

?????????
竟然不成功！