怎样在CWinApp中得到CView的指针

[w_j76]

我的程序中为class CHBCApp : public CWinApp；class CHBCView : public CFormView，怎样在CHBCApp 中得到CHBCView 的指针
I try
BOOL CHBCApp::OnIdle(LONG lCount)
{

CHBCView* myview=(CHBCView*)AfxGetMainWnd();

}

but it is error address
CHBCView* myview=(CHBCView*)GetMainWnd();
也一样；

[WhiteWaterBlueSky]

(CHBCView *)((CMainFrame *)(AfxGetApp()->m_pMainWnd))->GetActiveView()
得分啦！

[joke100]

从全局取视嘛...以前有很多这类的贴子.

如果是MDI多文档与SDI单文档界面略有不同...
步骤:
先全局取框架
用框架取CHILD窗口(对于MDI来讲)
用上面取的窗口取活动视


取视这个操作可以写成全局函数....因为入口取框架可以用全局函数取得
下面是MSDN上MDI的一个例子:
CMDIFrameWnd *pFrame =
(CMDIFrameWnd*)AfxGetApp()->m_pMainWnd;

// Get the active MDI child window.
CMDIChildWnd *pChild =
(CMDIChildWnd *) pFrame->GetActiveFrame();

// or CMDIChildWnd *pChild = pFrame->MDIGetActive();

// Get the active view attached to the active MDI child
// window.
CMyView *pView = (CMyView *) pChild->GetActiveView();

如果是SDI,那么:
CMyView *pView = NULL;
CFrameWnd* pWnd = AfxGetApp()->m_pMainWnd;
if (pWnd)
{
pView = (CMyView*)pWnd->GetActiveView();
}