类型转换，请指点，谢谢

[yaoliuba]

我的意思是，如果：

double dou=12.34;
我如何可以得到
char * ch="12.34";

转换函数是什么？

[yaoliuba]

谢谢了，我现在很急的！

[wyzegg]

double dou=12.34;
char * ch;
ch=malloc(100);
sprintf(ch,"%5.2f",dou);

[wyzegg]

或者
#include <stdlib.h>
#include <stdio.h>

void main( void )
{
int decimal, sign;
char *buffer;
int precision = 10;
double source = 3.1415926535;

buffer = _ecvt( source, precision, &decimal, &sign );
printf( "source: %2.10f buffer: '%s' decimal: %d sign: %d\n",
source, buffer, decimal, sign );
}

但是第一种常用

[Matrix_w]

int decimal, sign;
double dou =12.34;
char* ch;
ch = _ecvt(dou,4,&decimal,&sign);

[Matrix_w]

比我快一步...呵呵

[冰壶2013]

double dou=12.34;
char *str;
gcvt(dou,5,str); //5是长度
MessageBox(str);

[Matrix_w]

/* _GCVT.C: This program converts -3.1415e5
* to its string representation.
*/

#include <stdlib.h>
#include <stdio.h>

void main( void )
{
char buffer[50];
double source = -3.1415e5;
_gcvt( source, 7, buffer );
printf( "source: %f buffer: '%s'\n", source, buffer );
_gcvt( source, 7, buffer );
printf( "source: %e buffer: '%s'\n", source, buffer );
}


Output

source: -314150.000000 buffer: '-314150.'
source: -3.141500e+005 buffer: '-314150.'