欢迎熟悉Ajax或者Xajax进来
请问XAJAX怎么获得GET或者POST方法提交上来的数据,而且PHP页面好象要载入两次,把GET或者POST方法的数据刷没了.郁闷
请看如下代码(?????????部分):
<?php
session_start();
ini_set('include_path',dirname($_SERVER["SCRIPT_FILENAME"])."/include");
require_once ("include/xajax.inc.php");
require_once ('include/server.inc.php');
require_once ('include/factotry.inc.php');
require_once ('include/xajaxGrid.inc.php');
$grid=array();
$id=$_GET['id'];//???????????????/
?>
<?php
$xajax2 = new xajax();
$xajax2->decodeUTF8InputOn(); //使Ajax支持中文
// $xajax2->debugOn(); //进入调试模式
$xajax2->registerFunction("showGrid");
$xajax2->registerFunction("deleteAll");
$xajax2->processRequests('slow_function');
function getGET($request) {
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/2000/REC-xhtml1-20000126/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>资源细节</title>
<link rel="stylesheet" href="css/style.css" type="text/css" />
<LINK href="../skin/skin1/css.css" rel=stylesheet type=text/css>
<link rel="stylesheet" href="../css/pagetitle_css.css" type="text/css">
<script src="include/browse1.js" type="text/javascript" language="javascript"></script>
<?php echo $xajax2->getJavascript("include/") ?>
</head>
<body>
<br>
<center><div id="loadingMessage" ><img src="images/loading_16x16.gif" alt="" /> 数据正在载入...请稍后</div>
<table width="100%" border="0" style="background: #F9F9F9; padding: 0px;" align="left">
<tr>
<td align="left" style="padding: 0px;">
<fieldset>
<div id="grid" align="center"> </div>
<div id="formDiv" class="formDiv" ></div>
<div id="msgZone" class="formDiv" ></div>
<script type="text/javascript">
xajax_showGrid(0,<?php echo ROWSXPAGE?>,'','','<?php echo $grid['f_id']?>');
</script>
</fieldset>
</td>
</tr>
</table>
</center>
</body>
</html>