关于PHP变量的问题

[KAMCHIHAU]

这个是没问题的........
<?php
$var = '<script>document.write("liudehua")</script>';
echo $var////////////////////////出来的是liudehua
?>

这个却不行.......
<?php
$var = '<script>document.write("liudehua")</script>';
$query = mysql_query("select distinct xingming from biao where xingming='$var'");//这句SQL放了$var却不成
while($ass = mysql_fetch_assoc($query)){
echo $ass['xingming'];
}
?>

[faisun]

LZ 还没有弄清楚什么是客户端，什么是服务器端

[luojxun]

<?php
$var = ' <script >document.write("liudehua") </script > ';
echo $var////////////////////////出来的是liudehua
? >
要搞清echo $var是怎么执行的。其实首先由php打印出<script >document.write("liudehua") </script >然后javascript再打印出liudehua。

[码出钞能力]

楼主真可爱

[回炉重造，学习编程中。。。]

你有数据库吗？就select了

[dreambird1983]

$query = mysql_query("select distinct xingming from biao where xingming= '$var '");

======================等价于==================================================================

$query = mysql_query( "select distinct xingming from biao where xingming= \"<script >document.write(\'liudehua\') </script >\"" );

这样查询肯定是不行的