有文件list.txt 我想取出开头不含 building ,sent ,total 的所有行，怎么办呀

[caixicn]

有文件list.txt 我想取出开头不含 building ,sent ,total 的所有行，怎么办呀，我用正则试了很久，好像linux下的正则不一样??。。

我的做法,不过不行.

egrep "^(^(total |creating |sent |building ).*)$" list.txt 

list.txt

building file list ... done
./
hlo/
hfsdkfsd/
fsd/fasdf/safd/
hellopig.gif
fdsaf/fsdf/
sdfsdi.com
sent 700020 bytes  received 48 bytes  466712.00 bytes/sec
total size is 1586521359  speedup is 2266.24

[caixicn]

现在用了个土方法

awk '{ if (($0~/^.*\/$/)||($0~/^sent .*$/)||($0~/^total .*$/)||($0~/^building .*$/)||($0~/^creating .*$/)) {} else{print $0} }' list.txt

[yvqq]

egrep "total|building|send " -v list.txt