取得某一年的所有周六,周日的程序.

[qlknight]

有没有人写过输入一个年份,
输入该年的所有周六,周日的程序.

如果没有的话也可以给个建议.

谢谢

[yoyo82]

mark

[火龙果被占用了]

import java.util.Calendar;
import java.util.GregorianCalendar;

public class DateTest {

    public static void main(String[] args) {
        int year = 2011;
        Calendar calendar = new GregorianCalendar(year, 0, 1);
        int i = 1;
        while (calendar.get(Calendar.YEAR) < year + 1) {
            calendar.set(Calendar.WEEK_OF_YEAR, i++);
            calendar.set(Calendar.DAY_OF_WEEK, Calendar.SUNDAY);
            if (calendar.get(Calendar.YEAR) == year) {
                System.out.printf("星期天：%tF%n", calendar);
            }
            calendar.set(Calendar.DAY_OF_WEEK, Calendar.SATURDAY);
            if (calendar.get(Calendar.YEAR) == year) {
                System.out.printf("星期六：%tF%n", calendar);
            }
        }
    }
}

[hrcdg]

import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;

/**
 * 
 *
 */
public class Day {

	public static void main(String[] args) {
		
		SimpleDateFormat df=new SimpleDateFormat("yyyy-MM-dd");
		Calendar cal=Calendar.getInstance();
		int i = 1; //循环基数
		int year = 2007;//年份
		int week = Calendar.MONDAY;//指定的星期

		cal.set(Calendar.YEAR, year);
		for( i= 1; i <= 365/7;i++ ){
			cal.set(Calendar.WEEK_OF_YEAR, i);
			cal.set(Calendar.DAY_OF_WEEK, week);
			System.out.println(df.format(cal.getTime()));
		}
			cal.set(Calendar.WEEK_OF_YEAR, i);
			cal.set(Calendar.DAY_OF_WEEK, week);	
			
			int otherYear = cal.get(Calendar.YEAR);
			if(year==otherYear)
			System.out.println(df.format(cal.getTime()));
		
	}
}

[qlknight]

回3楼,
用365作为循环条件不太严谨吧.

[hrcdg]

回楼主

在这里是可以这样滴，365/7和366/7结果都是一样的。哥们！

import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;

/**
 * 
 *
 */
public class Day {

    public static void main(String[] args) {
        
        SimpleDateFormat df=new SimpleDateFormat("yyyy-MM-dd");
        Calendar cal=Calendar.getInstance();
        int i = 1; //循环基数
        int year = 2007;//年份
        int week = Calendar.MONDAY;//指定的星期

        cal.set(Calendar.YEAR, year);
        for( i= 1; i <= 365/7;i++ ){ //365跟366除以7的结果都是一样的，所以严谨性我觉得够。
            cal.set(Calendar.WEEK_OF_YEAR, i);
            cal.set(Calendar.DAY_OF_WEEK, week);
            System.out.println(df.format(cal.getTime()));
        }
            cal.set(Calendar.WEEK_OF_YEAR, i);//存在一种可能，在最后不满足一周的情况下还存在指定的星期，故继续让时间往下推一周
            cal.set(Calendar.DAY_OF_WEEK, week);    
            
            int otherYear = cal.get(Calendar.YEAR);
            if(year==otherYear)//如果还在当年，就将它取（打印）出来
            System.out.println(df.format(cal.getTime()));
        
    }
}