struts改变应用struts-config.xml如何修改配置？

[zengpb]

struts改变应用struts-config.xml如何修改配置？
原来有个应用abc,他是占用了tomcat的root目录，一切正常
struts-config.xml文件是
<action path="/search"
type="com.autonomy.action.SearchAction"
name="SearchForm"
scope="request"
parameter="action"
cancellable="false">
<forward name="search" path="/search_result.jsp"/>
<forward name="getdoc" path="/getcontent.jsp"/>
<forward name="suggest" path="/suggest.jsp"/>
</action>

<html:form action="/search.do?action=search" method="post">
.....
</html:form>
后来把它放入webapps下的abc

struts-config.xml中是否需要修改为
<forward name="suggest" path="/abc/suggest.jsp"/>
<html:form action="/abc/search.do?action=search" method="post">
怎么都设置不对？

http://localhost:8080/abc/search.do?action=suggest&id=26440
我现在直接访问他也提示

javax.servlet.ServletException: Cannot retrieve mapping for action:
"/abc/search"

org.apache.struts.chain.ComposableRequestProcessor.process(Composabl
essor.java:286)
org.apache.struts.action.ActionServlet.process(ActionServlet
org.apache.struts.action.ActionServlet.doGet(ActionServlet.j
javax.servlet.http.HttpServlet.service(HttpServlet.java:743)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)


晕了

[mailjoyo]

<action path="/add/search"
type="com.autonomy.action.SearchAction"
name="SearchForm"
scope="request"
parameter="action"
cancellable="false">
<forward name="search" path="/search_result.jsp"/>
<forward name="getdoc" path="/getcontent.jsp"/>
<forward name="suggest" path="/suggest.jsp"/>
</action>


加在红的地方试试
其他按照原样不变

[zengpb]

已经搞定，具体如何，参考我csdn 的 blog