c++二维数组输出问题!

[qnyniwvfp]

小弟刚刚学++,遇到一个练习题.
原代码是:
int A[7][7] =
{
{0,0,0,0,0,0,0},
{0,0,0,1,0,0,0},
{0,0,1,0,1,0,0},
{0,1,1,1,1,1,0},
{1,0,0,0,0,0,1},
{0,0,0,0,0,0,0},
{0,0,0,0,0,0,0},
};
for(int row = 0;row < 7; row++)
{
for(int col = 0; col < 7; col++)
{
if(A[row][col] == 0)
cout << ' ';
else
cout << '*';
}
　
cout << endl;
}
这样可以输出一个"A",题目要求不改变数组元索.改程序代码实现输出一个躺着的"A".
即:

[SenerityChzr]

只需要该一句话：

if(A[row][col] == 0)

改为：

if(A[col][row] == 0)

[zhangyanli]

很明显啊 ，把矩阵转一下不就是A了吗，可以调整一下循环实现

[zhangyanli]

代码如下：

#include<iostream>
using namespace std;
int A[7][7] =
{
{0,0,0,0,0,0,0},
{0,0,0,1,0,0,0},
{0,0,1,0,1,0,0},
{0,1,1,1,1,1,0},
{1,0,0,0,0,0,1},
{0,0,0,0,0,0,0},
{0,0,0,0,0,0,0},
};

int main()
{
for(int row = 0;row < 7; row++)
{
for(int col = 0; col < 7; col++)
{
if(A[col][row] == 0)
cout <<" ";
else
cout <<'*';
}
cout << endl;
}
return 0;
}

[zdd9804]

矩阵转置

[HelloDan]

#include<iostream>
#include<vector>
#include<string>

using namespace std;

int main()   
{   
  int A[7][7] =   
{   
      {0,0,0,0,0,0,0},   
      {0,0,0,1,0,0,0},   
      {0,0,1,0,1,0,0},   
      {0,1,1,1,1,1,0},   
      {1,0,0,0,0,0,1},   
      {0,0,0,0,0,0,0},   
      {0,0,0,0,0,0,0}   
}; 

for(int row=0;row<7;row++)   
{   
        for(int col=6;col>=0;col--)   
        {   
                if(A[col][row]==0)   
                      cout<<' ';   
                else   
                      cout<<'*';   
        }    
      cout<<endl;   
}   


   return 0;   
}   

[pptor]

矩阵转置

[License2Kill]

好题目

[qnyniwvfp]

謝謝!