如何获得enum成员的属性值？

[wxtp]

现在定义了一个名为People的枚举类型

[System.SerializableAttribute()]
public enum People {
        
        /// <remarks/>
        [System.Xml.Serialization.XmlEnumAttribute("Sam")]
        Item0,
        
        /// <remarks/>
        [System.Xml.Serialization.XmlEnumAttribute("John")]
        Item1,
        
        /// <remarks/>
        [System.Xml.Serialization.XmlEnumAttribute("Jimmy")]
        Item2,
     
    }

现在想通过一个函数

string GetAttribue(Type type, string itemname)

实现获取People枚举类型的属性值，就是GetAttribue(typeof(People), "Item0")返回"Sam"，GetAttribue(typeof(People), "Item1")返回"John"，GetAttribue(typeof(People), "Item2")返回"Jimmy"
那么GetAttribute该如何实现？

[王集鹄]

参考如下代码

using System.Reflection;

[System.SerializableAttribute()]
public enum People
{
    /// <remarks/>
    [System.Xml.Serialization.XmlEnumAttribute("Sam")]
    Item0,

    /// <remarks/>
    [System.Xml.Serialization.XmlEnumAttribute("John")]
    Item1,

    /// <remarks/>
    [System.Xml.Serialization.XmlEnumAttribute("Jimmy")]
    Item2,

}

private void button1_Click(object sender, EventArgs e)
{
    Text = GetAttribue(typeof(People), "Item0");
}

public static string GetAttribue(Type type, string itemname)
{
    FieldInfo vFieldInfo = type.GetField(itemname);
    Attribute vAttribute = Attribute.GetCustomAttribute(
        vFieldInfo, typeof(System.Xml.Serialization.XmlEnumAttribute));
    if (vAttribute != null)
        return ((System.Xml.Serialization.XmlEnumAttribute)vAttribute).Name;
    else return itemname;
}

[khler]

顶一下