请高手帮忙一下..sql.语法

[evilkoyou]

请高手帮忙一下..sql.语法

我要在下面列表中查出总合时间(ttime),又可以列出最近一笔日期的数据要这么做呢?

User_id test_area quest score ttime learn_time
S001 2^30 28 76 54 2008-06-27 10:47:00
S001 2^23 21 76 88 2008-06-22 10:47:00
S001 2^24 22 76 32 2008-06-21 10:47:00
S001 2^25 23 76 77 2008-06-20 10:47:00




=>
User_id test_area quest score learn_time total_ttime
S001 2^30 28 76 2008-06-27 10:47:00 251

[evilkoyou]

请高手帮忙一下..sql.语法

我要在下面列表中查出总合时间(ttime),又可以列出最近一笔日期的数据要这么做呢?

User_id test_area quest score ttime learn_time
S001 2^30 28 76 54 2008-06-27 10:47:00
S001 2^23 21 76 88 2008-06-22 10:47:00
S001 2^24 22 76 32 2008-06-21 10:47:00
S001 2^25 23 76 77 2008-06-20 10:47:00


=>
User_id test_area quest score learn_time total_ttime
S001 2^30 28 76 2008-06-27 10:47:00 251

[一铜钱&Moon]

select a.* into #total from (
SELECT top 1 [User_id]
      ,[test_area]
      ,[quest]
      ,[score]
      ,[ttime]
      ,[learn_time], 1 as total_ttime   
FROM [dbo].[A]
order by [learn_time] desc) a


declare @total int
 select @total =sum([ttime]) from [dbo].[A]
update #total
set total_ttime = @total

select * from #total

[-狙击手-]

select a.*,b.total_time
from tablea a 
left join (select user_id,sum(ttime) as total_time from tablea group by user_id) b
on a.user_id = b.user_id
where not exists(select 1 from tablea where a.userid = userid and learn_time < a.learn_time)

[中国风]

use test
go
declare @T table(User_id char(4),     test_area nvarchar(4),  quest int,   score int,  ttime   int,            learn_time datetime)
insert @T select 'S001',                     '2^30',             28,         76,             54,           '2008-06-27   10:47:00' 
insert @T select 'S001',                     '2^23',             21,         76,             88,           '2008-06-22   10:47:00' 
insert @T select 'S001',                     '2^24',             22,         76,             32,           '2008-06-21   10:47:00' 
insert @T select 'S001',                     '2^25',             23,         76,             77,           '2008-06-20   10:47:00'

select 
	User_id,test_area,quest,score,
	[ttime]=(select sum(ttime) from @t where User_id=t.User_id),
	learn_time
 from 
	@T  t 
where 
	not exists(select 1 from @T where User_id=t.User_id and learn_time>t.learn_time) 

ser_id test_area quest       score       ttime       learn_time                                             
------- --------- ----------- ----------- ----------- ------------------------------------------------------ 
S001    2^30      28          76          251         2008-06-27 10:47:00.000

（所影响的行数为 1 行）

[中国风]

或:

use test
go
declare @T table(User_id char(4),     test_area nvarchar(4),  quest int,   score int,  ttime   int,            learn_time datetime)
insert @T select 'S001',                     '2^30',             28,         76,             54,           '2008-06-27   10:47:00' 
insert @T select 'S001',                     '2^23',             21,         76,             88,           '2008-06-22   10:47:00' 
insert @T select 'S001',                     '2^24',             22,         76,             32,           '2008-06-21   10:47:00' 
insert @T select 'S001',                     '2^25',             23,         76,             77,           '2008-06-20   10:47:00'

select 
	User_id,test_area,quest,score,
	[ttime]=(select sum(ttime) from @t where User_id=t.User_id),
	learn_time
 from 
	@T  t 
where 
	learn_time=(select max(learn_time) from @T where User_id=t.User_id) 


User_id test_area quest       score       ttime       learn_time                                             
------- --------- ----------- ----------- ----------- ------------------------------------------------------ 
S001    2^30      28          76          251         2008-06-27 10:47:00.000

（所影响的行数为 1 行）

[-狙击手-]

declare @T table(User_id char(4),     test_area nvarchar(4),  quest int,   score int,  ttime   int,            learn_time datetime)
insert @T select 'S001',                     '2^30',             28,         76,             54,           '2008-06-27   10:47:00' 
insert @T select 'S001',                     '2^23',             21,         76,             88,           '2008-06-22   10:47:00' 
insert @T select 'S001',                     '2^24',             22,         76,             32,           '2008-06-21   10:47:00' 
insert @T select 'S001',                     '2^25',             23,         76,             77,           '2008-06-20   10:47:00'

select a.*,b.total_time
from @T a 
left join (select user_id,sum(ttime) as total_time from @T group by user_id) b
on a.user_id = b.user_id
where not exists(select 1 from @T where a.user_id = user_id and learn_time > a.learn_time)
/*

User_id test_area quest       score       ttime       learn_time                                             total_time  
------- --------- ----------- ----------- ----------- ------------------------------------------------------ ----------- 
S001    2^30      28          76          54          2008-06-27 10:47:00.000                                251

（所影响的行数为 1 行）

*/

[cxmcxm]

--假设表名为t1
select t1.user_id,t1.test_area,t1.quest,t1.score,t1.learn_time,a.total_ttime
(select user_id,max(learn_time) learn_time,sum(ttime) total_ttime from t1 group by user_id) a,
t1
where a.user_id=t1.user_id and a.learn_time=t1.learn_time