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shui1212 2007-12-05 02:57:38

B
1
5
-3
2
5
3
-2
-8

5
-2
...全文
48 点赞 收藏 9

9 条回复

kk19840210 2007-12-05
``````
create table #a (b int)
insert into #a values(1)
insert into #a values(5)
insert into #a values(-3)
insert into #a values(2)
insert into #a values(5)
insert into #a values(3)
insert into #a values(-2)
insert into #a values(-8)

create table #b(b int)

select id=identity(int,0,1) ,b into # from #a

insert into #b
select b=sum(b) from # group by id/4

select * from #b

b
-----------
5
-2

(2 行受影响)

``````

kelph 2007-12-05
select identity(int,1,0) as id ,b into # from table

insert into b
select sum(b)
from #
group by id/4

drop table #

-狙击手- 2007-12-05

select identity(int,0,1) as id ,b into # from tabe

chuifengde 2007-12-05
``````declare @a table(a int)
insert @a select 1
union all select 5
union all select -3
union all select 2
union all select 5
union all select 3
union all select -2
union all select -8

declare @b table(id int identity(0,1),a int)
insert @b select * from @a

select sum(a) from @b group by id/4
--result
/*
-----------
5
-2

（所影响的行数为 2 行）*/``````

kelph 2007-12-05

dawugui 2007-12-05
``````create table A(B int)
insert into A values(1)
insert into A values(5)
insert into A values(-3)
insert into A values(2)
insert into A values(5)
insert into A values(3)
insert into A values(-2)
insert into A values(-8)
create table B(B int)
go

select B , id = identity(int,0,1) into tmp from A

insert into B select 结果 from (select id = id/4 , 结果 = sum(B) from tmp group by id/4) t

select * from B

drop table A,B,tmp

/*
B
-----------
5
-2

（所影响的行数为 2 行）
*/``````

dawugui 2007-12-05
``````create table A(B int)
insert into A values(1)
insert into A values(5)
insert into A values(-3)
insert into A values(2)
insert into A values(5)
insert into A values(3)
insert into A values(-2)
insert into A values(-8)
go
select B , id = identity(int,0,1) into tmp from A

select id/4 , 结果 = sum(B) from tmp group by id/4

drop table A,tmp

/*
结果
----------- -----------
0           5
1           -2

（所影响的行数为 2 行）

*/``````

-狙击手- 2007-12-05
select identity(int,1,0) as id ,b into # from tabe

insert into b
select id,sum(b)
from #
group by id

drop table #

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