循环写数据

[shui1212]

读取表A的B项（int）记录，以4条数据为单位，求和之后写入表B中，求代码？
例：
表A
B
1
5
-3
2
5
3
-2
-8
写入表B后为
5
-2

[-狙击手-]

select identity(int,1,0) as id ,b into # from tabe


insert into b
select id,sum(b)
from #
group by id

drop table #

[dawugui]

create table A(B int)
insert into A values(1) 
insert into A values(5) 
insert into A values(-3) 
insert into A values(2) 
insert into A values(5) 
insert into A values(3) 
insert into A values(-2) 
insert into A values(-8)
go
select B , id = identity(int,0,1) into tmp from A

select id/4 , 结果 = sum(B) from tmp group by id/4

drop table A,tmp

/*
            结果          
----------- ----------- 
0           5
1           -2

（所影响的行数为 2 行）

*/

[dawugui]

create table A(B int)
insert into A values(1) 
insert into A values(5) 
insert into A values(-3) 
insert into A values(2) 
insert into A values(5) 
insert into A values(3) 
insert into A values(-2) 
insert into A values(-8)
create table B(B int)
go

select B , id = identity(int,0,1) into tmp from A

insert into B select 结果 from (select id = id/4 , 结果 = sum(B) from tmp group by id/4) t

select * from B

drop table A,B,tmp

/*
B           
----------- 
5
-2

（所影响的行数为 2 行）
*/

[chuifengde]

declare @a table(a int)
insert @a select 1 
union all select 5 
union all select -3 
union all select 2 
union all select 5 
union all select 3 
union all select -2 
union all select -8 

declare @b table(id int identity(0,1),a int)
insert @b select * from @a

select sum(a) from @b group by id/4
--result
/*
----------- 
5
-2

（所影响的行数为 2 行）*/

[kelph]

如果最后一组不够四条了怎么处理，剩下的算一组吗？

[-狙击手-]

不好意思　，我把函数参数搞错
select identity(int,0,1) as id ,b into # from tabe

[kelph]

select identity(int,1,0) as id ,b into # from table


insert into b
select sum(b)
from #
group by id/4


drop table #

[kk19840210]

create table #a (b int)
insert into #a values(1)
insert into #a values(5)
insert into #a values(-3)
insert into #a values(2)
insert into #a values(5)
insert into #a values(3)
insert into #a values(-2)
insert into #a values(-8)

create table #b(b int)

select id=identity(int,0,1) ,b into # from #a

insert into #b 
select b=sum(b) from # group by id/4 

select * from #b


b
-----------
5
-2

(2 行受影响)

[火星求索]

按最后一组个数计算和