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表A的字段减去表B的字段之和，如何写SQL语句？
情况大致如下：
表A：
id1 id2 id3 dj sl
a1 a2 a3 3 100
b1 b2 b3 5 50
......
表A是存货表，id1、id2、id3是货物信息，dj表示单价，sl表示数量。
表B：
id1 id2 id3 dj sl
a1 a2 a3 3 45
a1 a2 a3 3 15
b1 b2 b3 5 20
.......
表B是出货表，sl表示从表A中取出的货物数量。
现在想做一个查询，显示的记录如下：
id1 id2 id3 dj sl
a1 a2 a3 3 40
b1 b2 b3 5 30
也就是这里显示的sl是表A的sl减去表B数量之和，40=100-45-15 ， 30=50-20，
SQL语句该如何写，多谢大家！！！
表A：
id1 id2 id3 dj sl
a1 a2 a3 3 100
b1 b2 b3 5 50
......
表A是存货表，id1、id2、id3是货物信息，dj表示单价，sl表示数量。
表B：
id1 id2 id3 dj sl
a1 a2 a3 3 45
a1 a2 a3 3 15
b1 b2 b3 5 20
.......
表B是出货表，sl表示从表A中取出的货物数量。
现在想做一个查询，显示的记录如下：
id1 id2 id3 dj sl
a1 a2 a3 3 40
b1 b2 b3 5 30
也就是这里显示的sl是表A的sl减去表B数量之和，40=100-45-15 ， 30=50-20，
SQL语句该如何写，多谢大家！！！
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-狙击手- 2007-12-06
B表是多条呀
select a.id1,a.id2,a.id3,a.dj ,sum(a.sl - b.sl)
from tablea a
left join (select id1,id2,ide3 ,sum(sl)as sl from tableb group by id1,ide2,id3) b
on a.id1 = b.id1 and a.id2 = b.id2 and a.id3 = b.id3
group by a.id1,a.id2,a.id3
select a.id1,a.id2,a.id3,a.dj ,sum(a.sl - b.sl)
from tablea a
left join (select id1,id2,ide3 ,sum(sl)as sl from tableb group by id1,ide2,id3) b
on a.id1 = b.id1 and a.id2 = b.id2 and a.id3 = b.id3
group by a.id1,a.id2,a.id3
duanzhi1984 2007-12-06
try
--
select a.id1,a.id2,a.id3,a.dj,a.sl-b.sl as sl
from A a join (select id1,id2,id3,dj,sum(sl) sl from B group by id1,id2,id3,dj) b
on a.id=b.id and a.id2=b.id2 and a.id3=b.id3
--
select a.id1,a.id2,a.id3,a.dj,a.sl-b.sl as sl
from A a join (select id1,id2,id3,dj,sum(sl) sl from B group by id1,id2,id3,dj) b
on a.id=b.id and a.id2=b.id2 and a.id3=b.id3
-狙击手- 2007-12-06
select a.id1,a.id2,a.id3,a.dj ,sum(a.sl - b.sl)
from tablea a
left join tableb b
on a.id1 = b.id1 and a.id2 = b.id2 and a.id3 = b.id3
group by a.id1,a.id2,a.id3中国风 2007-12-06
select
a.id1,a.id2,a.id3,a.dj,
[sl]=a.sl-t.s1
from
a
join
(select id1,id2,id3,sum(sl)as s1 from b group by id1,id2,id3)T
on t.id1=a.id1 and t.id2=a.id2 and t.id3=a.id3中国风 2007-12-06
select
a.id1,a.id2,a.id3,a.dj,
[sl]=a.sl-(select sum(sl) from b where id1=a.id1 and id2=a.id2 and id3=a.id3)
from
a中国风 2007-12-06
select
a.id1,a.id2,a.id3,a.dj,
[sl]=a.sl-(select sum() from b where id1=a.id1 and id2=a.id2 and id3=a.id3)
from
a