VC->java

[chaoxy21cn]

int Calc_crc(unsigned char len,
unsigned char *in, unsigned char *out)//CRC
{
int i, j, stat;
unsigned int crc;
stat=0x31e3;

// CRC16 // crc = 0xC78C; // bit-swapped 0x31E3
crc = 0x31E3;
for (j=0;j<len; j++)
{
crc=crc^((unsigned int)in[j]<<8);
for (i=0;i<8;i++)
{
if (crc&0x8000)
crc=(crc<<1)^0x1021;
else crc=crc<<1;
}
}
out[0]=(unsigned char)(crc>>8);
out[1]=(unsigned char)crc;
if (crc)
stat=1;

return (stat);
}

[chaoxy21cn]

将这段VC代码转换成JAVA代码,多谢...

[椅子来了]

和谐接分

[qybao]

have a try

    int calc_Crc(int len, byte[] in, byte[] out) {
	    int i, j, stat;
	    char crc;
	    
	    stat = 0x31e3;
	    crc  = 0x31E3; 
	    
	    for (j=0; j<len; j++) { 
	      crc = (char)(crc^(in[j]<<8)); 
	      
	      for (i=0; i<8; i++) { 
	          if ((crc & 0x8000) > 0) crc = (char)((crc<<1)^0x1021);   
	          else crc <<= 1;
	      } 
	    
	      out[0]=(byte)(crc>>8); 
	      out[1]=(byte)crc;
	      
	      if (crc > 0) stat=1; 
	      
	      return stat; 
	}

[chaoxy21cn]

多谢,阿宝兄
我自己也写一个,算出的结果跟你的一样,可是与VC算出来的高位不对
/** update CRC with byte b */
public String encode2(byte[] aByte)
{
int crc;
crc = 0x31E3;
byte[] out = new byte[2];;
for (int j = 0; j < aByte.length; j++) {
crc=crc^((int)aByte[j]<<8);
for (int i=0;i<8;i++)
{
if ((crc&0x8000)>0)
crc=(crc<<1)^0x1021;
else
crc=crc<<1;
}

}
out[0]=(byte)(crc>>8);
out[1]=(byte)crc;
try{
return new String(out,"gbk");
}catch (Exception ex){
return "";
}
}
byte[] b = new byte[]{(byte)0x5A,(byte)0x01,(byte)0x1A};
算出来是:3F 31.
VC算出来是AE 31

[qybao]

我算出来是AE31，跟你的VC结果一样啊

    public static void main(String[] args) {
        byte[] in = {(byte)0x5A,(byte)0x01,(byte)0x1A}; 
        byte[] out = new byte[2];
        int stat = calc_Crc(3, in, out);
        for (int i=0; i<out.length; i++) {
            System.out.printf("%02X", new Object[]{new Byte(out[i])});
        }
        System.out.println();
    }

    static int calc_Crc(int len, byte[] in, byte[] out) {
	int i, j, stat;
	char crc;
	    
	stat = 0x31e3;
	crc  = 0x31E3; 
	    
	for (j=0; j<len; j++) { 
	  crc = (char)(crc^(in[j]<<8)); 
	      
	  for (i=0; i<8; i++) { 
	      if ((crc & 0x8000) > 0) crc = (char)((crc<<1)^0x1021);   
	      else crc <<= 1;
	  }
	}
	    
	  out[0]=(byte)(crc>>8); 
	  out[1]=(byte)crc;
	      
	  if ((int)crc > 0) stat=1; 

	  return stat; 
    }
    
    

输出结果
AE31

LZ的方法也没什么大问题，你把
return new String(out,"gbk");
改成
return new String(out);
就可以了

[yanhan0615]

好几天没来CSDN,这么容易的分都没接上

[chaoxy21cn]

这几天忙晕了.给份了.呵