java 正则表达式高分求解

[gypb]

字符串
abasdfasdf $asdfasd$ andfdf $df$ adskflasdf
asdfasdf $123$ asdfasfd

需要用正则表达式找出所有用$包含的字符串，
如上列字符串，需要返回$asdfasd$,$df$,$123$

[angues1980]

下面这个应该行

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {

	public static void main(String[] args) {
		String target="abasdfasdf   $asdfasd$   andfdf   $df$   adskflasdf asdfasdf   $123$   asdfasfd ";
		
		List list = new ArrayList();
		
		 Pattern p = Pattern.compile("\\S*[\\$]\\S*");
		 Matcher m = p.matcher(target);
		 while(m.find()){
			 list.add(m.group());
		 }
		 System.out.println(list);
	}

}

\S指的是非空白的字符
*是0或多个
$是特殊符号需要转义所以写成\$
就这些吧

千万要结贴啊，就等着这些分穿下个裤衩呢

[dracularking]

也可以这样

Pattern p = Pattern.compile("[\\$]\\S*");

[吴恒]

import java.io.*;
import java.net.*;
import java.util.regex.*;


public class HrefMatch
{
public static void main(String[] args)
{
try
{
// get URL string from command line or use default
String urlString;
String input;
// open reader for URL


// read contents into string buffer

input ="abasdfasdf $asdfasd$ andfdf $df$ adskflasdf asdfasdf $123$ asdfasfd ";

// search for all occurrences of pattern
String patternString = "\\S*[\\$]\\S*";
Pattern pattern = Pattern.compile(patternString);
Matcher matcher = pattern.matcher(input);

while (matcher.find())
{
int start = matcher.start();
int end = matcher.end();
String match = input.substring(start, end);
System.out.println(match);
}
}

catch (PatternSyntaxException e)
{
e.printStackTrace();
}
}
}

[angues1980]

嗯，想复杂了
我想的是含有$的所以字符串了

[吴恒]

import java.io.*;
import java.net.*;
import java.util.regex.*;


public class HrefMatch
{
public static void main(String[] args)
{
try
{
// get URL string from command line or use default
String urlString;
String input;
// open reader for URL


// read contents into string buffer

input ="abasdfasdf $asdfasd$ andfdf $df$ adskflasdf asdfasdf $123$ asdfasfd ";

// search for all occurrences of pattern
String patternString = "\\s+[\\$]\\S+[\\$]\\s+";
Pattern pattern = Pattern.compile(patternString);
Matcher matcher = pattern.matcher(input);

while (matcher.find())
{
int start = matcher.start();
int end = matcher.end();
String match = input.substring(start, end);
System.out.println(match);
}
}

catch (PatternSyntaxException e)
{
e.printStackTrace();
}
}
}

[angues1980]

其实要这么说的话，应该改成下面这样的才严格符合要求

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {

	public static void main(String[] args) {
		String target="abasdfasdf   $asdfasd$   andfdf   $df$   adskflasdf asdfasdf   $123$   asdfasfd ";
		
		List list = new ArrayList();
		
		Pattern p = Pattern.compile(" \\$\\S+\\$ ");
		Matcher m = p.matcher(" " + target + " ");
		 while(m.find()){
			 list.add(m.group().trim());
		 }
		 System.out.println(list);
	}

}

[angues1980]

5楼的代码有个问题，因为如果第一个字符串是符合要求的，是不会被检出来的