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pzp 2001-07-27
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thank you everyone,我刚看过msdn,应该是pow(),^ is 异或。
kane_yj 2001-07-27
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#include <math.h>
#include <stdio.h>
void main( void )
{
double x = 2.0, y = 3.0, z;
z = pow( x, y );
printf( "%.1f to the power of %.1f is %.1f\n", x, y, z );
}
Output
2.0 to the power of 3.0 is 8.0
-----msdn
#include <stdio.h>
void main( void )
{
double x = 2.0, y = 3.0, z;
z = pow( x, y );
printf( "%.1f to the power of %.1f is %.1f\n", x, y, z );
}
Output
2.0 to the power of 3.0 is 8.0
-----msdn
zeroweb 2001-07-27
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^
_STLer 2001-07-27
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^
horris 2001-07-27
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函数pow
