select * from [用户注册表] where cast(substring(ip,charindex('.',ip,charindex('.',ip, charindex('.',ip,0)+1)+1)+1, len(ip)-charindex('.',ip,charindex('.',ip, charindex('.',ip,0)+1)+1)) as integer) between 5 and 79
28,391
社区成员
357,060
社区内容
加载中
试试用AI创作助手写篇文章吧