高分求一条SQL语句的实现!敬请帮忙,谢谢!

[Sammo]

请问,以下要求,在SQL Server2000里可不可以使用一条SQL语句实现?要是可以,如何实现呢?谢谢!

表A的数据结构:
A_Code,A_Name,A_Amount1,A_Amount2,A_Amount3
1001,张三,1000,2000,3000
2001,李四,4000,5000,6000

表B的数据结构:
A_Code,B_Code,B_Amount
1001,10011,1000
1001,10012,2000
2001,20011,2000
2001,20012,3000
2001,20013,5000

要想通过SQL语句把表A和表B的数据合成,得出结果的表C数据结构:
A_Code,A_Name,C_TatolNum,C_Amount,C_Per
1001,张三,2,3000,50.00%
2001,李四,3,10000,66.67%


其中表C的数据来源:
C_TotalNum=Select count(*) From B Where B_Amount>0
C_Amount=Select Sum(B_Amount) From B
C_Per=B_Amount/(A_Amount1+A_Amount2+A_Amount3) //得出数据格式为50.05%

[liangCK]

create table ta(A_Code int,A_Name varchar(20),A_Amount1 int,A_Amount2 int,A_Amount3 int)
insert into ta select 1001,'张三',1000,2000,3000 
insert into ta select 2001,'李四',4000,5000,6000

create table tb(A_Code int,B_Code int,B_Amount int)
insert into tb select 1001,10011,1000 
insert into tb select 1001,10012,2000 
insert into tb select 2001,20011,2000 
insert into tb select 2001,20012,3000 
insert into tb select 2001,20013,5000

select a.A_Code,a.A_Name,b.C_TotalNum,b.B_Amount,cast(b.B_Amount*100.0/c.num as decimal(10,2)) C_Per
from ta a,(select A_Code,sum(B_Amount) B_Amount,count(*) C_TotalNum from tb group by A_Code) b
      ,(select A_Code,sum(num) num
        from(select A_Code,A_Amount1 as num from ta
           union all select A_Code,A_Amount2 from ta
           union all select A_Code,A_Amount3 from ta) d
         group by A_Code) c
where a.A_Code=b.A_Code and a.A_Code=c.A_Code

drop table ta,tb

/*
A_Code      A_Name               C_TotalNum  B_Amount    C_Per        
----------- -------------------- ----------- ----------- ------------ 
1001        张三                   2           3000        50.00
2001        李四                   3           10000       66.67

（所影响的行数为 2 行）
*/

[dobear_0922]

create table A(A_Code int, A_Name varchar(16), A_Amount1 int, A_Amount2 int, A_Amount3 int) 
insert A select 1001, '张三',1000,2000,3000 
union all select 2001,'李四',4000,5000,6000 

go
create table B(A_Code int, B_Code int, B_Amount int) 
insert B select 1001,10011,1000 
union all select 1001,10012,2000 
union all select 2001,20011,2000 
union all select 2001,20012,3000 
union all select 2001,20013,5000 

go
select A.A_Code, A_Name
	,C_TatolNum=Num
	,C_Amount=Amount
	,C_Per=rtrim(cast(Amount*100.0/(A_Amount1+A_Amount2+A_Amount3) as decimal(5,2)))+'%'
from A join 
(
	select A_Code, Num=sum(case when B_Amount>0 then 1 else 0 end), Amount=sum(B_Amount) from B group by A_Code
) B on A.A_Code=B.A_Code

/*
A_Code      A_Name           C_TatolNum  C_Amount    C_Per
----------- ---------------- ----------- ----------- ------------------------------------------
1001        张三               2           3000        50.00%
2001        李四               3           10000       66.67%

(2 row(s) affected)
*/

drop table A,B

[liangCK]

create table ta(A_Code int,A_Name varchar(20),A_Amount1 int,A_Amount2 int,A_Amount3 int)
insert into ta select 1001,'张三',1000,2000,3000 
insert into ta select 2001,'李四',4000,5000,6000

create table tb(A_Code int,B_Code int,B_Amount int)
insert into tb select 1001,10011,1000 
insert into tb select 1001,10012,2000 
insert into tb select 2001,20011,2000 
insert into tb select 2001,20012,3000 
insert into tb select 2001,20013,5000

select a.A_Code,a.A_Name,b.C_TotalNum,b.B_Amount,
            cast(cast(b.B_Amount*100.0/c.num as decimal(10,2)) as varchar)+'%' C_Per
from ta a,(select A_Code,sum(B_Amount) B_Amount,count(*) C_TotalNum from tb group by A_Code) b
      ,(select A_Code,sum(num) num
        from(select A_Code,A_Amount1 as num from ta
           union all select A_Code,A_Amount2 from ta
           union all select A_Code,A_Amount3 from ta) d
         group by A_Code) c
where a.A_Code=b.A_Code and a.A_Code=c.A_Code

drop table ta,tb

/*
A_Code      A_Name               C_TotalNum  B_Amount    C_Per                           
----------- -------------------- ----------- ----------- ------------------------------- 
1001        张三                   2           3000        50.00%
2001        李四                   3           10000       66.67%

（所影响的行数为 2 行）
*/

[liangCK]

学习一下do熊的.的搞得太复杂了..

[dobear_0922]

其中表C的数据来源:
C_TotalNum=Select count(*) From B Where B_Amount> 0

-----------
小梁，你好像没用到这个条件，，，

[liangCK]

是哦..
那case判断一下就好了.

..学习一下.

[Sammo]

强,谢谢两位!SQL使用得很精通哦.羡慕,请问哪里有SQL学习的好书啊?请推荐两本,谢谢!
结贴.

[liangCK]

rtrim(cast(Amount*100.0/(A_Amount1+A_Amount2+A_Amount3) as decimal(5,2)))+'%'

忘了可以这样子的..害我绕了个大圈..看来得好好学习.

[liangCK]

这分给得不好哦..
平分就好嘛.

[Sammo]

呵呵.因为我觉得给50分给dobear_0922不够,因为他写的确实很精简明了,所以就按七三分了.呵呵...不好意思,LiangCK,我再补分给你好吗?

[Sammo]

我想把这个查询语句做成视图来调用:
select A.A_Code, A_Name
,C_TatolNum=Num
,C_Amount=Amount
,C_Per=rtrim(cast(Amount*100.0/(A_Amount1+A_Amount2+A_Amount3) as decimal(5,2)))+'%'
from A join
(
select A_Code, Num=sum(case when B_Amount>0 then 1 else 0 end), Amount=sum(B_Amount) from B group by A_Code
) B on A.A_Code=B.A_Code

提示错误:查询设计器不支持 CASE SQL 构造。
怎么办呢?

[liangCK]

我用do熊的数据

create table A(A_Code int, A_Name varchar(16), A_Amount1 int, A_Amount2 int, A_Amount3 int) 
insert A select 1001, '张三',1000,2000,3000 
union all select 2001,'李四',4000,5000,6000 

go
create table B(A_Code int, B_Code int, B_Amount int) 
insert B select 1001,10011,1000 
union all select 1001,10012,2000 
union all select 2001,20011,2000 
union all select 2001,20012,3000 
union all select 2001,20013,5000 
go

create view v_test
as 
select A.A_Code, A_Name
    ,C_TatolNum=Num
    ,C_Amount=Amount
    ,C_Per=rtrim(cast(Amount*100.0/(A_Amount1+A_Amount2+A_Amount3) as decimal(5,2)))+'%'
from A join 
(
    select A_Code, Num=sum(case when B_Amount>0 then 1 else 0 end), Amount=sum(B_Amount) from B group by A_Code
) B on A.A_Code=B.A_Code

go