如何把下面unicode的数字用正则表达式提取出来?

[wfront]

比如字符串"aaavbvv流c行ddff飾zzz8品584", 怎样用正则表达式把unicode里面的数字提取出来?
最好只用java.util.regex的class
下面是企图把每个unicode提取出来的代码, 为什么达不到目的?应该怎样改?

String str = "aaavbvv流c行ddff飾zzz8品584";
	String regex = "&#\\d{5};";
	Pattern p = Pattern.compile(regex);
	Matcher m = p.matcher(str);
	if(m.find()){
	for (int i = 1; i <= m.groupCount(); i++) {
	    System.out.println(m.group(i));
	}
}

[goodmrning]

关注

[healer_kx]

"&#[0-9]{5};";

[jaqcy]

    String str = "aaavbvv流c行ddff飾zzz8品584";
    String regex = "&#(\\d{5});";
    Pattern p = Pattern.compile(regex);
    Matcher m = p.matcher(str);
    while(m.find()){
String s=m.group();
        System.out.println(s);
        str=str.replaceAll("&#"+s+";","");
    }
}