String 转换 date

[MattHgh]

这样就能转换

String nowTime="2008-01-18";
Date date = java.sql.Date.valueOf(nowTime);
System.out.println(date);

但是,带上时间就不行

String nowTime="2008-01-18 09:10:10";
Date date = java.sql.Date.valueOf(nowTime);
System.out.println(date);

怎么把String nowTime="2008-01-18 09:10:10";带时间也转换成date类型??
转换为这样格式的SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

[eidolon_warrior]

String nowTime="2008-01-18 09:10:10";
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date day = df.parse(nowTime);

[L_Spring]

參考一下API中的Calendar類吧，不建議再使用Date類

[MattHgh]

to eidolon_warrior

这样他输出的是
Fri Jan 18 09:10:10 CST 2008
可以是2008-01-18 09:10:10吗

[c2one]

java.sql.Date的概念只有年月日
看java.sql.Date.valueOf(String)的原码

	public static Date valueOf(String s) {
		int year;
		int month;
		int day;
		int firstDash;
		int secondDash;

		if (s == null)
			throw new java.lang.IllegalArgumentException();

		firstDash = s.indexOf('-');
		secondDash = s.indexOf('-', firstDash + 1);
		if ((firstDash > 0) & (secondDash > 0) & (secondDash < s.length() - 1)) {
			year = Integer.parseInt(s.substring(0, firstDash)) - 1900;
			month = Integer.parseInt(s.substring(firstDash + 1, secondDash)) - 1;
			day = Integer.parseInt(s.substring(secondDash + 1));
		} else {
			throw new java.lang.IllegalArgumentException();
		}

		return new Date(year, month, day);
	}

使用SimpleDateFormat转没问题啊

		SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd   HH:mm:ss");
		try {
			Date data = df.parse("2008-01-18   09:10:10");
			System.out.println(data);
		} catch (ParseException e) {
			e.printStackTrace();
		}