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--少括号了
select CardNo,sum(datediff(mi,convert(varchar(10),IODate,120)+' 17:30',dt)) as 加班总时间
from (select CardNo,case when IOTime <'07:00:00' then dateadd(day,-1,IODate) else IODate end as IODate,max(cast(convert(varchar(10),IODate,120)+' '+IOTime as datetime)) as Dt
from tab group by CardNo,case when IOTime <'07:00:00' then dateadd(day,-1,IODate) else IODate end
) as t
group by CardNo
--不如日期时间放一个字段方便
select CardNo,sum(datediff(mi,convert(varchar(10),IODate,120)+' 17:30',dt) as 加班总时间
from (select CardNo,case when IOTime <'07:00:00' then dateadd(day,-1,IODate) else IODate end as IODate,max(cast(convert(varchar(10),IODate,120)+' '+IOTime as datetime)) as Dt
from tab group by CardNo,case when IOTime <'07:00:00' then dateadd(day,-1,IODate) else IODate end
) as t
group by CardNo
--这个可能会把17:37的正常下班打卡计算了7分钟加班
--如果不算跨天,且加班时间最小以一个小时计算。
select cardno , 小时 = sum(datediff(hh , convert(varchar(10),io_date,120) + ' 17:30:00' , convert(varchar(10),io_date,120) + ' ' + iotime)) from
(
select t.* from tb t where IOTime = (select max(IOTime) from tb where cardno = t.cardno and iodate = t.iodate)
) m
group by cardno
--按某一字段分组取最大(小)值所在行的数据
(爱新觉罗.毓华 2007-10-23于浙江杭州)
/*
数据如下:
name val memo
a 2 a2(a的第二个值)
a 1 a1--a的第一个值
a 3 a3:a的第三个值
b 1 b1--b的第一个值
b 3 b3:b的第三个值
b 2 b2b2b2b2
b 4 b4b4
b 5 b5b5b5b5b5
*/
--创建表并插入数据:
create table tb(name varchar(10),val int,memo varchar(20))
insert into tb values('a', 2, 'a2(a的第二个值)')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('b', 1, 'b1--b的第一个值')
insert into tb values('b', 3, 'b3:b的第三个值')
insert into tb values('b', 2, 'b2b2b2b2')
insert into tb values('b', 4, 'b4b4')
insert into tb values('b', 5, 'b5b5b5b5b5')
go
--一、按name分组取val最大的值所在行的数据。
--方法1:
select a.* from tb a where val = (select max(val) from tb where name = a.name) order by a.name
--方法2:
select a.* from tb a where not exists(select 1 from tb where name = a.name and val > a.val)
--方法3:
select a.* from tb a,(select name,max(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
--方法4:
select a.* from tb a inner join (select name , max(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name
--方法5
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name
/*
name val memo
---------- ----------- --------------------
a 3 a3:a的第三个值
b 5 b5b5b5b5b5
*/
--二、按name分组取val最小的值所在行的数据。
--方法1:
select a.* from tb a where val = (select min(val) from tb where name = a.name) order by a.name
--方法2:
select a.* from tb a where not exists(select 1 from tb where name = a.name and val < a.val)
--方法3:
select a.* from tb a,(select name,min(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
--方法4:
select a.* from tb a inner join (select name , min(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name
--方法5
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val < a.val) order by a.name
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 1 b1--b的第一个值
*/
--三、按name分组取第一次出现的行所在的数据。
select a.* from tb a where val = (select top 1 val from tb where name = a.name) order by a.name
/*
name val memo
---------- ----------- --------------------
a 2 a2(a的第二个值)
b 1 b1--b的第一个值
*/
--四、按name分组随机取一条数据。
select a.* from tb a where val = (select top 1 val from tb where name = a.name order by newid()) order by a.name
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 5 b5b5b5b5b5
*/
--五、按name分组取最小的两个(N个)val
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val < a.val ) order by a.name,a.val
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val) order by a.name,a.val
select a.* from tb a where exists (select count(*) from tb where name = a.name and val < a.val having Count(*) < 2) order by a.name
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
a 2 a2(a的第二个值)
b 1 b1--b的第一个值
b 2 b2b2b2b2
*/
--六、按name分组取最大的两个(N个)val
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name,a.val
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val desc) order by a.name,a.val
select a.* from tb a where exists (select count(*) from tb where name = a.name and val > a.val having Count(*) < 2) order by a.name
/*
name val memo
---------- ----------- --------------------
a 2 a2(a的第二个值)
a 3 a3:a的第三个值
b 4 b4b4
b 5 b5b5b5b5b5
*/
--七,如果整行数据有重复,所有的列都相同。
/*
数据如下:
name val memo
a 2 a2(a的第二个值)
a 1 a1--a的第一个值
a 1 a1--a的第一个值
a 3 a3:a的第三个值
a 3 a3:a的第三个值
b 1 b1--b的第一个值
b 3 b3:b的第三个值
b 2 b2b2b2b2
b 4 b4b4
b 5 b5b5b5b5b5
*/
--在sql server 2000中只能用一个临时表来解决,生成一个自增列,先对val取最大或最小,然后再通过自增列来取数据。
--创建表并插入数据:
create table tb(name varchar(10),val int,memo varchar(20))
insert into tb values('a', 2, 'a2(a的第二个值)')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('b', 1, 'b1--b的第一个值')
insert into tb values('b', 3, 'b3:b的第三个值')
insert into tb values('b', 2, 'b2b2b2b2')
insert into tb values('b', 4, 'b4b4')
insert into tb values('b', 5, 'b5b5b5b5b5')
go
select * , px = identity(int,1,1) into tmp from tb
select m.name,m.val,m.memo from
(
select t.* from tmp t where val = (select min(val) from tmp where name = t.name)
) m where px = (select min(px) from
(
select t.* from tmp t where val = (select min(val) from tmp where name = t.name)
) n where n.name = m.name)
drop table tb,tmp
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 1 b1--b的第一个值
(2 行受影响)
*/
--在sql server 2005中可以使用row_number函数,不需要使用临时表。
--创建表并插入数据:
create table tb(name varchar(10),val int,memo varchar(20))
insert into tb values('a', 2, 'a2(a的第二个值)')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('b', 1, 'b1--b的第一个值')
insert into tb values('b', 3, 'b3:b的第三个值')
insert into tb values('b', 2, 'b2b2b2b2')
insert into tb values('b', 4, 'b4b4')
insert into tb values('b', 5, 'b5b5b5b5b5')
go
select m.name,m.val,m.memo from
(
select * , px = row_number() over(order by name , val) from tb
) m where px = (select min(px) from
(
select * , px = row_number() over(order by name , val) from tb
) n where n.name = m.name)
drop table tb
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 1 b1--b的第一个值
(2 行受影响)
*/
--可以说不好办,第二天凌晨的卡记录
--不会是第二天上班的吗?所以还需要一个时间点来
--区分凌晨的哪个时间点之前属于前天,之后属于当天!!
create table tb(CardNo int, IODate datetime, IOTime varchar(32))
insert tb select 217, '2007-1-25', '17:37:19'
union all select 217, '2007-1-25', '17:39:49'
union all select 217, '2007-1-25', '17:39:58'
union all select 217, '2007-1-25', '17:40:45'
union all select 97, '2007-1-25', '17:43:26'
union all select 97, '2007-1-25', '17:43:32'
union all select 217, '2007-1-25', '17:44:40'
union all select 217, '2007-1-25', '17:46:34'
union all select 152, '2007-1-25', '18:43:17'
union all select 217, '2007-1-25', '18:43:23'
union all select 152, '2007-1-25', '18:43:31'
union all select 152, '2007-1-25', '18:43:34'
union all select 346, '2007-1-25', '18:45:59'
union all select 346, '2007-1-25', '18:46:04'
union all select 346, '2007-1-25', '18:46:07'
union all select 175, '2007-1-25', '18:46:31'
union all select 217, '2007-1-25', '18:46:47'
union all select 179, '2007-1-25', '18:49:39'
union all select 179, '2007-1-26', '06:49:39' --加上此行测试加班到凌晨的情况
select CardNo
, '总加班时间(分钟)'=sum(datediff(mi, '17:30:00', IOTime))
, '总加班时间(小时)'=sum(datediff(mi, '17:30:00', IOTime))/60.0
from
(
select CardNO, IODate, IOTime=max(IOTime) from
(
select CardNO, IODate, IOTime from tb where datediff(mi, '17:30:00', IOTime)>0 --改下,过滤掉'17:30:00'之前的
union all
select CardNO, dateadd(d,-1,IODate), dateadd(d,1,IOTime) from tb where datepart(hh,IOTime)<7
) T group by CardNO, IODate
) T
group by CardNO
/*
CardNo 总加班时间(分钟) 总加班时间(小时)
----------- ----------- ---------------------------------------
97 13 0.216666
152 73 1.216666
175 76 1.266666
179 799 13.316666
217 76 1.266666
346 76 1.266666
(6 row(s) affected)
*/
drop table tb
create table tb(CardNo int, IODate datetime, IOTime varchar(32))
insert tb select 217, '2007-1-25', '17:37:19'
union all select 217, '2007-1-25', '17:39:49'
union all select 217, '2007-1-25', '17:39:58'
union all select 217, '2007-1-25', '17:40:45'
union all select 97, '2007-1-25', '17:43:26'
union all select 97, '2007-1-25', '17:43:32'
union all select 217, '2007-1-25', '17:44:40'
union all select 217, '2007-1-25', '17:46:34'
union all select 152, '2007-1-25', '18:43:17'
union all select 217, '2007-1-25', '18:43:23'
union all select 152, '2007-1-25', '18:43:31'
union all select 152, '2007-1-25', '18:43:34'
union all select 346, '2007-1-25', '18:45:59'
union all select 346, '2007-1-25', '18:46:04'
union all select 346, '2007-1-25', '18:46:07'
union all select 175, '2007-1-25', '18:46:31'
union all select 217, '2007-1-25', '18:46:47'
union all select 179, '2007-1-25', '18:49:39'
union all select 179, '2007-1-26', '06:49:39' --加上此行测试加班到凌晨的情况
select CardNo
, '总加班时间(分钟)'=sum(datediff(mi, '17:30:00', IOTime))
, '总加班时间(小时)'=sum(datediff(mi, '17:30:00', IOTime))/60.0
from
(
select CardNO, IODate, IOTime=max(IOTime) from
(
select CardNO, IODate, IOTime from tb where datepart(hh,IOTime)>=7
union all
select CardNO, dateadd(d,-1,IODate), dateadd(d,1,IOTime) from tb where datepart(hh,IOTime)<7
) T group by CardNO, IODate
) T
group by CardNO
/*
CardNo 总加班时间(分钟) 总加班时间(小时)
----------- ----------- ---------------------------------------
97 13 0.216666
152 73 1.216666
175 76 1.266666
179 799 13.316666
217 76 1.266666
346 76 1.266666
(6 row(s) affected)
*/
drop table tb