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请高手帮忙，20分，只要能解决，不够再加

hww2004 2008-02-26 02:12:06

有如下表：A,
CUS_NO PRD_NO S_DD UP
====== ======= ========== =====
A BAD001 2007-12-01 2.0
A BAD001 2008-01-21 2.2
A BAD001 2008-02-15 2.1
B BAD001 2008-01-11 2.2
B BAD001 2008-02-22 2.3
C BAD001 2008-02-21 2.2
C BAD001 2008-02-23 2.1
A1 BAD002 2008-01-21 2.2
A2 BAD002 2008-01-21 2.3
A2 BAD002 2008-01-26 2.2
... ... ... ...
例如：希望将BAD001对应CUS_NO中取A,BAD001,2008-02-15(最近日期)的记录 ,
希望取如下结果后的补集合：
CUS_NO PRD_NO S_DD UP
====== ======= ========== =====
A BAD001 2008-02-15 2.1
B BAD001 2008-02-22 2.3
C BAD001 2008-02-23 2.1
A1 BAD002 2008-01-21 2.2
A2 BAD002 2008-01-26 2.2
个人感觉比较难描述，就将需求结果列示出来让大家容易看懂。
请专家、高手帮忙！重谢！

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切换为时间正序

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pt1314917 2008-02-26

晕。8楼的不是行吗？

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-狙击手- 2008-02-26

create table A(CUS_NO varchar(8),PRD_NO varchar(10),S_DD datetime,UP decimal(9,2))

go

insert into A

select 'A','BAD001','2007-12-01',2.0

union select 'A','BAD001','2008-01-21',2.2

union select 'A','BAD001','2008-02-15',2.1

union select 'B','BAD001','2008-01-11',2.2

union select 'B','BAD001','2008-02-22',2.3

union select 'C','BAD001','2008-02-21',2.2

union select 'C','BAD001','2008-02-23',2.1

union select 'A1','BAD002','2008-01-21',2.2

union select 'A2','BAD002','2008-01-21',2.3

union select 'A2','BAD002','2008-01-26',2.3

union select 'A2','BAD002','2008-01-26',2.2

go

select * from A

select cus_no,prd_no,s_dd,up 

from A 

where not exists(select * 

                 from A b

                 where datepart(yy,a.S_DD)= datepart(yy,b.S_DD) and a.cus_no=b.cus_no and a.prd_no=b.prd_no and a.s_dd > b.s_dd ) 

order by len(cus_no),cus_no

go

drop table A;

go

/*



cus_no   prd_no     s_dd                                                   up          

-------- ---------- ------------------------------------------------------ ----------- 

A        BAD001     2007-12-01 00:00:00.000                                2.00

A        BAD001     2008-01-21 00:00:00.000                                2.20

B        BAD001     2008-01-11 00:00:00.000                                2.20

C        BAD001     2008-02-21 00:00:00.000                                2.20

A1       BAD002     2008-01-21 00:00:00.000                                2.20

A2       BAD002     2008-01-21 00:00:00.000                                2.30



（所影响的行数为 6 行）

*/

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pt1314917 2008-02-26



--哦。明白搂主的意思了。。





select * from ta a where  exists

(select 1 from ta where CUS_NO=a.CUS_NO and PRD_NO=a.PRD_NO and S_DD>a.S_DD)

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-狙击手- 2008-02-26

CUS_NO PRD_NO S_DD UP
======= =========== ==== =====
A BAD001 2007-12-01 2.0
A BAD001 2008-01-21 2.2
B BAD001 2008-01-11 2.2
C BAD001 2008-02-21 2.2
A2 BAD002 2008-01-21 2.3

------------------------

A BAD001 2007-12-01 2.0
A BAD001 2008-01-21 2.2
一样的？

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pt1314917 2008-02-26



--怎么每天都有无数个这种类型的题目啊



select * from 表名 a where not exists

(select 1 from 表名 where CUS_NO=a.CUS_NO and PRD_NO=a.PRD_NO and S_DD>a.S_DD)

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hww2004 2008-02-26

wzh1215:
您好，您的语句仍然有问题。希望的结果是：
CUS_NO PRD_NO S_DD UP
======= =========== ==== =====
A BAD001 2007-12-01 2.0
A BAD001 2008-01-21 2.2
B BAD001 2008-01-11 2.2
C BAD001 2008-02-21 2.2
A2 BAD002 2008-01-21 2.3

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wzh1215 2008-02-26

select * from A
where not exists(select 1 from A AA where A.CUS_NO=AA.CUS_NO AND A.PRD_NO=AA.PRD_NO AND A.S_DD>AA.S_DD)

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zefuzhang2008 2008-02-26

with t as(select t.*,row_number() over(PARTITION BY CUS_NO order by  S_DD desc) as rowid

 from t)

select CUS_NO,PRD_NO,S_DD,UP                              

from t

where rowid=1

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liangCK 2008-02-26

create table A(CUS_NO varchar(8),PRD_NO varchar(10),S_DD datetime,UP decimal(9,2))

go

insert into A

select 'A','BAD001','2007-12-01',2.0

union select 'A','BAD001','2008-01-21',2.2

union select 'A','BAD001','2008-02-15',2.1

union select 'B','BAD001','2008-01-11',2.2

union select 'B','BAD001','2008-02-22',2.3

union select 'C','BAD001','2008-02-21',2.2

union select 'C','BAD001','2008-02-23',2.1

union select 'A1','BAD002','2008-01-21',2.2

union select 'A2','BAD002','2008-01-21',2.3

union select 'A2','BAD002','2008-01-26',2.3

union select 'A2','BAD002','2008-01-26',2.2

go

select * from A;

select cus_no,prd_no,s_dd,up 

from A 

where not exists(select * from A b where a.cus_no=b.cus_no and a.prd_no=b.prd_no and checksum(a.s_dd,a.up)>checksum(b.s_dd,b.up)) 

order by len(cus_no),cus_no

go

drop table A;

go



(11 行受影响)

CUS_NO   PRD_NO     S_DD                    UP

-------- ---------- ----------------------- ---------------------------------------

A        BAD001     2007-12-01 00:00:00.000 2.00

A        BAD001     2008-01-21 00:00:00.000 2.20

A        BAD001     2008-02-15 00:00:00.000 2.10

A1       BAD002     2008-01-21 00:00:00.000 2.20

A2       BAD002     2008-01-21 00:00:00.000 2.30

A2       BAD002     2008-01-26 00:00:00.000 2.20

A2       BAD002     2008-01-26 00:00:00.000 2.30

B        BAD001     2008-01-11 00:00:00.000 2.20

B        BAD001     2008-02-22 00:00:00.000 2.30

C        BAD001     2008-02-21 00:00:00.000 2.20

C        BAD001     2008-02-23 00:00:00.000 2.10



(11 行受影响)



cus_no   prd_no     s_dd                    up

-------- ---------- ----------------------- ---------------------------------------

A        BAD001     2008-02-15 00:00:00.000 2.10

B        BAD001     2008-02-22 00:00:00.000 2.30

C        BAD001     2008-02-23 00:00:00.000 2.10

A1       BAD002     2008-01-21 00:00:00.000 2.20

A2       BAD002     2008-01-21 00:00:00.000 2.30



(5 行受影响)

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liangCK 2008-02-26

--按某一字段分组取最大(小)值所在行的数据

(爱新觉罗.毓华 2007-10-23于浙江杭州)

/*

数据如下：

name val memo

a    2   a2(a的第二个值)

a    1   a1--a的第一个值

a    3   a3:a的第三个值

b    1   b1--b的第一个值

b    3   b3:b的第三个值

b    2   b2b2b2b2

b    4   b4b4

b    5   b5b5b5b5b5

*/

--创建表并插入数据：

create table tb(name varchar(10),val int,memo varchar(20))

insert into tb values('a',    2,   'a2(a的第二个值)')

insert into tb values('a',    1,   'a1--a的第一个值')

insert into tb values('a',    3,   'a3:a的第三个值')

insert into tb values('b',    1,   'b1--b的第一个值')

insert into tb values('b',    3,   'b3:b的第三个值')

insert into tb values('b',    2,   'b2b2b2b2')

insert into tb values('b',    4,   'b4b4')

insert into tb values('b',    5,   'b5b5b5b5b5')

go



--一、按name分组取val最大的值所在行的数据。

--方法1：

select a.* from tb a where val = (select max(val) from tb where name = a.name) order by a.name

--方法2：

select a.* from tb a where not exists(select 1 from tb where name = a.name and val > a.val)

--方法3：

select a.* from tb a,(select name,max(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name

--方法4：

select a.* from tb a inner join (select name , max(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name

--方法5

select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name

/*

name       val         memo                 

---------- ----------- -------------------- 

a          3           a3:a的第三个值

b          5           b5b5b5b5b5

*/



--二、按name分组取val最小的值所在行的数据。

--方法1：

select a.* from tb a where val = (select min(val) from tb where name = a.name) order by a.name

--方法2：

select a.* from tb a where not exists(select 1 from tb where name = a.name and val < a.val)

--方法3：

select a.* from tb a,(select name,min(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name

--方法4：

select a.* from tb a inner join (select name , min(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name

--方法5

select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val < a.val) order by a.name

/*

name       val         memo                 

---------- ----------- -------------------- 

a          1           a1--a的第一个值

b          1           b1--b的第一个值

*/



--三、按name分组取第一次出现的行所在的数据。

select a.* from tb a where val = (select top 1 val from tb where name = a.name) order by a.name

/*

name       val         memo                 

---------- ----------- -------------------- 

a          2           a2(a的第二个值)

b          1           b1--b的第一个值

*/



--四、按name分组随机取一条数据。

select a.* from tb a where val = (select top 1 val from tb where name = a.name order by newid()) order by a.name

/*

name       val         memo                 

---------- ----------- -------------------- 

a          1           a1--a的第一个值

b          5           b5b5b5b5b5

*/



--五、按name分组取最小的两个(N个)val

select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val < a.val ) order by a.name,a.val

select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val) order by a.name,a.val

select a.* from tb a where exists (select count(*) from tb where name = a.name and val < a.val having Count(*) < 2) order by a.name

/*

name       val         memo                 

---------- ----------- -------------------- 

a          1           a1--a的第一个值

a          2           a2(a的第二个值)

b          1           b1--b的第一个值

b          2           b2b2b2b2

*/



--六、按name分组取最大的两个(N个)val

select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name,a.val

select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val desc) order by a.name,a.val

select a.* from tb a where exists (select count(*) from tb where name = a.name and val > a.val having Count(*) < 2) order by a.name

/*

name       val         memo                 

---------- ----------- -------------------- 

a          2           a2(a的第二个值)

a          3           a3:a的第三个值

b          4           b4b4

b          5           b5b5b5b5b5

*/

--七，如果整行数据有重复，所有的列都相同。

/*

数据如下：

name val memo

a    2   a2(a的第二个值)

a    1   a1--a的第一个值

a    1   a1--a的第一个值

a    3   a3:a的第三个值

a    3   a3:a的第三个值

b    1   b1--b的第一个值

b    3   b3:b的第三个值

b    2   b2b2b2b2

b    4   b4b4

b    5   b5b5b5b5b5

*/

--在sql server 2000中只能用一个临时表来解决，生成一个自增列，先对val取最大或最小，然后再通过自增列来取数据。

--创建表并插入数据：

create table tb(name varchar(10),val int,memo varchar(20))

insert into tb values('a',    2,   'a2(a的第二个值)')

insert into tb values('a',    1,   'a1--a的第一个值')

insert into tb values('a',    1,   'a1--a的第一个值')

insert into tb values('a',    3,   'a3:a的第三个值')

insert into tb values('a',    3,   'a3:a的第三个值')

insert into tb values('b',    1,   'b1--b的第一个值')

insert into tb values('b',    3,   'b3:b的第三个值')

insert into tb values('b',    2,   'b2b2b2b2')

insert into tb values('b',    4,   'b4b4')

insert into tb values('b',    5,   'b5b5b5b5b5')

go



select * , px = identity(int,1,1) into tmp from tb



select m.name,m.val,m.memo from

(

  select t.* from tmp t where val = (select min(val) from tmp where name = t.name)

) m where px = (select min(px) from

(

  select t.* from tmp t where val = (select min(val) from tmp where name = t.name)

) n where n.name = m.name)



drop table tb,tmp



/*

name       val         memo

---------- ----------- --------------------

a          1           a1--a的第一个值

b          1           b1--b的第一个值



(2 行受影响)

*/

--在sql server 2005中可以使用row_number函数，不需要使用临时表。

--创建表并插入数据：

create table tb(name varchar(10),val int,memo varchar(20))

insert into tb values('a',    2,   'a2(a的第二个值)')

insert into tb values('a',    1,   'a1--a的第一个值')

insert into tb values('a',    1,   'a1--a的第一个值')

insert into tb values('a',    3,   'a3:a的第三个值')

insert into tb values('a',    3,   'a3:a的第三个值')

insert into tb values('b',    1,   'b1--b的第一个值')

insert into tb values('b',    3,   'b3:b的第三个值')

insert into tb values('b',    2,   'b2b2b2b2')

insert into tb values('b',    4,   'b4b4')

insert into tb values('b',    5,   'b5b5b5b5b5')

go



select m.name,m.val,m.memo from

(

  select * , px = row_number() over(order by name , val) from tb

) m where px = (select min(px) from

(

  select * , px = row_number() over(order by name , val) from tb

) n where n.name = m.name)



drop table tb



/*

name       val         memo

---------- ----------- --------------------

a          1           a1--a的第一个值

b          1           b1--b的第一个值



(2 行受影响)

*/