麻烦看下，这个程序哪有问题？内存错在哪了？谢谢

[dataowner]

//将字符串中连续的字母归并为一个,例如aaabbcdd -> abcd
void Fun(const char *a)
{
if(a == NULL)
return;
int len = sizeof(a);
char *p = new char[len];
if(p == NULL)
return;
memset(p,0,len);

while((*a) != '\0')
{
int i = 0;
while(*(p+i) != 0)
{
if(*(p+i) == *a)
break;
i++;
}
if(i==strlen(p))
*(p + i) = *a;
a++;
}
cout <<p;
delete []p;
p = NULL;
}

[baihacker]

int len = sizeof(a);
char *p = new char[len];

int len = strlen(a);
char *p = new char[len+1];

[baihacker]

//勉强能用
void   Fun(const   char   *a) 
{ 
	if(!a) return; 

	int		i		= 0;
	int		len		=   strlen(a); 
	char	*p		=   new   char[len+1]; 


	while (*a)
	{
		while (a[1]==a[0]) a++;
		p[i++] = *a++;
	}
	p[i] = 0;

	cout << p << endl;

	delete   []p; 
	p   =   NULL; 
}

[lin_style]

		if(*(p+i)   ==   *a)
			break;
		i++;

我猜你的意思是如果一样， 就把i相加，然后跳出，对a进行处理吧
写反了
要

		if(*(p+i)   ==   *a)
{
  i++;

			break;
}
		

[hityct1]

int len = sizeof(a);
显然不对
应为：
int len = strlen(a);

[dataowner]

hehe,就是int len = sizeof(a);传入指针永远是4...
谢谢大家。