提问： RegExp $X 问题……

[dylanOK]

搞了个String 替换，想用数组这样便于扩展，但replace那句过不去……


var NumArr = new Array();
NumArr["１"]=1;
NumArr["２"]=2;
NumArr["３"]=3;
NumArr["４"]=4;
NumArr["５"]=5;
NumArr["６"]=6;
NumArr["７"]=7;
NumArr["８"]=8;
NumArr["９"]=9;
NumArr["０"]=0;

var str="１";
var reg = new RegExp("(１|２|３|４|５|６|７|８|９|０)","gi");
str = str.replace(reg,NumArr[$1]);

[wjmmml]

jdk1.3没有replace这个函数，解决办法：
要么升级jdk到1.4。要么用我给你的下面的函数：
public String stringReplace(String sourceString, String toReplaceString, String replaceString)
{
String returnString = sourceString;
int stringLength = 0;
if(toReplaceString != null)
{
stringLength = toReplaceString.length();
}
if(returnString != null && returnString.length() > stringLength)
{
int max = 0;
String S4 = "";
for(int i = 0; i < sourceString.length(); i++)
{
max = i + toReplaceString.length() > sourceString.length()? sourceString.length():i + stringLength;
String S3 = sourceString.substring(i, max);
if(!S3.equals(toReplaceString))
{
S4 += S3.substring(0,1);
}else{
S4 += replaceString;
i += stringLength -1 ;
}
}
returnString = S4;
}
return returnString;
}

[wjmmml]

哦，是js啊，好象我弄错了，我以为是java呢，呵
那你就检查一下，是不是你给的参数类型不对。

[dylanOK]

老大，这里是JavaScript 版呀！

[qiushuiwuhen]

js5.5+
<script>
var NumArr = new Array();
NumArr["１"]=1;
NumArr["２"]=2;
NumArr["３"]=3;
NumArr["４"]=4;
NumArr["５"]=5;
NumArr["６"]=6;
NumArr["７"]=7;
NumArr["８"]=8;
NumArr["９"]=9;
NumArr["０"]=0;

var str="１８";
var reg = new RegExp("(１|２|３|４|５|６|７|８|９|０)","gi");
str = str.replace(reg,function($1){return NumArr[$1]});
alert(str)
</script>

[qiushuiwuhen]

js5.5以下
<script>
var NumArr = new Array();
NumArr["１"]=1;
NumArr["２"]=2;
NumArr["３"]=3;
NumArr["４"]=4;
NumArr["５"]=5;
NumArr["６"]=6;
NumArr["７"]=7;
NumArr["８"]=8;
NumArr["９"]=9;
NumArr["０"]=0;

var str="１８";
for(ob in NumArr)str=str.replace(new RegExp(ob,"gi"),NumArr[ob]);
alert(str)
</script>

[dylanOK]

好！谢谢秋水！^O^