如何从弹出一个页面,在转回原来的页面?
isaxu 2002-11-22 11:43:12 ShowMovieType.php页面中:
<script language="JavaScript">
<!--
function OpenShowMovieTypeTree()
{
newwin=window.open("ShowMovieTypeTree.php","ShowMovieTypeTree","left=0,top=0,width=400,height=450");
newwin.focus();
}
</script >
我现在想从ShowMovieTypeTree.php跳倒search_result.php,可是直接<a href='admin_select_result1.php?typename=a' ><strong>影片类型</strong></a>的话,查询结果还是显示在弹出的小页面中,我想把查询结果也就是'admin_select_result1.php显示在整个的页面上,也就是最初的ShowMovieType.php页,怎么做呢?
请大虾帮忙,不胜感激!!