新请教,关于java+xml开发

[suhu]

我是一个新手,请教如有如下一个XML,我应如何做:
<?xml version="1.0" encoding="UTF-8"?>
<Orders>
<Customer>
<NameEntry>
<FirstName>Pierce</FirstName>
<LastName>Bronson</LastName>
<EMail>[e-mail]</EMail>
</NameEntry>
<Order>
<Name>Where the Sidewalk Ends</Name>
<Author>Shel Silverstein</Author>
<Price>$5.95</Price>
<Detail>
<Carrier>United Airlines</Carrier>
<SKU>411AAA</SKU>
</Detail>
</Order>
<Date>7/7/97</Date>
</Customer>
<Customer>
<NameEntry>
<FirstName>Don</FirstName>
<LastName>Johnson</LastName>
<EMail>[e-mail]</EMail>
</NameEntry>
<Order>
<Name>Where the Sidewalk Begins</Name>
<Author>Shelley Long</Author>
<Price>$59.50</Price>
<Detail>
<Carrier>American Airlines</Carrier>
<SKU>AAA411</SKU>
</Detail>
</Order>
<Date>8/8/98</Date>
</Customer>
</Orders>
==================================================

我用的是:import org.w3c.dom.*;
问题一:
我将如何得到:<name>=Where the Sidewalk Begins
节点上:<Price>的值.
问题二:

我如何得到:
<name>=Where the Sidewalk Begins
这个点节.(反回一个NODE)

在线等待.最好有简单列子.

[Patrick_DK]

few points to do:(

[xiaoysh]

先假设你第二个问题解决了
应该可以用getParentNode获得其父节点，然后用
getChildNodes().item(i);就可以了吧

而第二个问题本身我想也可以类似取得

[suhu]

但我只知道这个条件:<name>=Where the Sidewalk Begins
并不知道item(I)

[xiaoysh]

那可以用循环判断嘛，每个item都编历一次

[cool_2000]

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance() ;
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(filename);
Element order = null;
Element name = null;
Element price = null;
Element root = doc.getDocumentElement();//get root element
NodeList rootlist = root.getChildNodes();
for (int i = 0; i < rootlist.getLength(); i++) {
Element customer = (Element) list.item(i);//get customer element
NodeList customerlist = custormer.getChildNodes();
for (int j = 0; j < customerlist.getLength(); j++) {
if (custormerlist.item(j).getNodeName().equals("order") ) {
order = customerlist.item(j);//get order ele
break;
}
}
}
if (order.hasChildNodes()) {
NodeList orderlist = order.getChildNodes();
for (int m = 0; m < orderlist.getLength(); m++) {
if (orderlist.item(m).getNodeName().equals("name") {
name = orderlist.item(m);//get name element
}
if (orderlist.item(m).getNodeName().equals("price") {
price = orderlist.item(m);//get price element
}
}
}
if (price != null && price.hasChildNodes()) {
String str = price.getFirstChild().getNodeValue();//get price value
}

[cool_2000]

记得多给分啊,我打个死啊

[cool_2000]

每次用Nodelist.item()所得结果请进行强制类型转化为Element.