怎么样用JavaScript或者JScript将“2003-1-6”这样的格式转换成“2003-01-06”这样的格式？

[nioued]

怎么样用JavaScript或者JScript将“2003-1-6”这样的格式转换成“2003-01-06”这样的格式？

[beauty_beast]

<script language=javascript>
function changedate(temp)
{ arrdate=temp.split('-');
if (arrdate.length<2)
{return temp;}
else
{
if (arrdate[1].length==1)
{arrdate[1]="0"+arrdate[1];}
if (arrdate[2].length==1)
{arrdate[2]="0"+arrdate[2];}
return arrdate.join("-");
}

}

</script>

[wangyime]

用split分割后在做判断吧，如果月或日小于等于9就加一个0

[二师兄的老公]

同意！

[希偌]

var re=/([0-9]{4})-([0-9]{1})-([0-9]{1})/g;
var s="2003-1-6";
s=s.replace(re,"$1-0$2-0$3");
alert(re.length());

[希偌]

function a() {
var re = new RegExp("([0-9]{4})-([0-9]{1,2})-([0-9]{1,2})","ig");
var s="2003-1-6";
re.exec(s);
var year,month,day;
year=RegExp.$1;
month=RegExp.$2.length==1?"0"+RegExp.$2:RegExp.$2;
day=RegExp.$3.length==1?"0"+RegExp.$3:RegExp.$3;
alert(year+"-"+month+"-"+day);
}

[qiushuiwuhen]

<script>
function a(s){return s.replace(/-(\d)(?=\D|$)/g,"-0$1");}
alert(a("2003-1-6"));
alert(a("2003-10-6"));
alert(a("2003-1-16"));
</script>

[希偌]

秋水来了，甘拜下风