问个傻傻的问题，如何接收某个servlet的response；

greenboat 2003-03-25 10:11:02

比如:jsp中用form post提交了一请求给某servlet，该servlet经处理后生成一response，我现要在前面那个jsp中得到该response，该怎么做呢？

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sparkwu 2003-03-25

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Modify:
Try it:
jsp1.htm
<HTML>
<BODY>
<FORM ACTION="jsp/jsp1.jsp" METHOD="POST">
<INPUT NAME="sample" VALUE="">
<BUTTON TYPE="SUBMIT">
SUBMIT
</BUTTON>
</FORM>
</BODY>
</HTML>

jsp1.jsp
<HTML>
<BODY>
<%
String param1 = request.getParameter("sample");
if (param1 != null)
{
RequestDispatcher rd = request.getRequestDispatcher("/servlet/practice.Servlet1");
rd.forward(request, response);
}
else
{
out.println("No selections were made");
}
%>
</BODY>
</HTML>

Servlet1.java
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;

public class Servlet1 extends HttpServlet
{
private static final String CONTENT_TYPE = "text/html";
/**Initialize global variables*/
public void init(ServletConfig config) throws ServletException
{
super.init(config);
}

public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType(CONTENT_TYPE);

// The following gets the original value posted in the HTML form:
String aString = request.getParameter("sample");
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<head><title>Servlet1</title></head>");
out.println("<body>");
out.println("<p>Servlet 1 has received a POST. This is the reply:</p>");
out.println(aString);
out.println("</body></html>");

// This is an example of how to forward a post
RequestDispatcher rd = request.getRequestDispatcher("jsp/jsp1.jsp");
rd.include(request, response);
}

/**Clean up resources*/
public void destroy()
{
}
}

sparkwu 2003-03-25

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Try it:
jsp1.htm
<HTML>
<BODY>
<FORM ACTION="jsp/jsp1.jsp" METHOD="POST">
<INPUT NAME="sample" VALUE="">
<BUTTON TYPE="SUBMIT">
SUBMIT
</BUTTON>
</FORM>
</BODY>
</HTML>

jsp1.jsp
<HTML>
<BODY>
<%
String param1 = request.getParameter("sample");
if (param1 != null)
{
RequestDispatcher rd = request.getRequestDispatcher("/servlet/practice.Servlet1");
rd.forward(request, response);
}
else
{
out.println("No selections were made");
}
%>
</BODY>
</HTML>

Servlet1.java
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;

public class Servlet1 extends HttpServlet
{
private static final String CONTENT_TYPE = "text/html";
/**Initialize global variables*/
public void init(ServletConfig config) throws ServletException
{
super.init(config);
}

public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType(CONTENT_TYPE);

// The following gets the original value posted in the HTML form:
String aString = request.getParameter("sample");
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<head><title>Servlet1</title></head>");
out.println("<body>");

// This shows the data from the post from choices.html
out.println("<p>Servlet 1 has received a POST. This is the reply:</p>");
out.println(aString);
out.println("</body></html>");

// This is an example of how to forward a post (in this case from choices.html to servlet2):
RequestDispatcher rd = request.getRequestDispatcher("jsp/jsp1.jsp");
rd.include(request, response);
}

/**Clean up resources*/
public void destroy()
{
}
}

dybine 2003-03-25

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jsp也是编译成servlet执行的，有response、request、session等对象的

greenboat 2003-03-25

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这些应些在servlet中吧，在jsp中是否直接就可用response对象了。

kreven 2003-03-25

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同意

jcq 2003-03-25

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RequestDispatcher rd = request.getRequestDispatcher(url);
rd.forward(request, response);

greenboat 2003-03-25

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能不能说的详细点。最好写几句代码，就一目了然了。

jcq 2003-03-25

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forward

greenboat 2003-03-25

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我想在servlet中把数据写到response中的stream中，没想到他却输出在屏幕上了。
DataOutputStream out = new DataOutputStream(response.getOutputStream));
out.writeByte("hello");
怎么会在屏幕上输出呢？

我在serlvet中写了
RequestDispatcher rd = request.getRequestDispatcher("resJsp.jsp");
rd.forward(request, response);
在resJsp中，应怎样接收呢？