疑难问题！！！

[dairy1]

一个是人员表
infoid(主键，自增长）,name,birthday,....

一个是证件表(一个人可能有0或多个证件记录）
infoid,idcardtype(证件类型：2护照，3港澳证....),idcardno(证件号)

想要得到
name,birthday,idcardtype1,idcardno1,idcardcardtype2,idcardno2

要求，一行中有两个证件类型与证件号，如果有护照，则护照为第一个证件号，其它任意选择一个证件号
如果没有护照，则任意选择两个

如何用一句SQL语句给出，不要用存储过程游标等

[pt1314917]

create table 人员表 (infoid int identity(1,1),name varchar(50),birthday datetime)
insert into 人员表  select 'a',getdate()
insert into 人员表  select 'b',getdate()
insert into 人员表  select 'c',getdate()
insert into 人员表  select 'd',getdate()

create table 证件表 (infoid int,idcardtype int,idcardno varchar(50))
insert into 证件表  select 1,2,'a11'
insert into 证件表  select 1,3,'a22'
insert into 证件表  select 1,4,'a33'
insert into 证件表  select 2,2,'b11'
insert into 证件表  select 2,3,'b22'
insert into 证件表  select 2,4,'b33'
insert into 证件表  select 3,2,'c11'
insert into 证件表  select 3,3,'c22'
insert into 证件表  select 3,4,'c33'
insert into 证件表  select 4,2,'d11'
insert into 证件表  select 4,3,'d22'
insert into 证件表  select 4,4,'d33'

select name,birthday,
(select top 1 idcardtype from 证件表 where infoid=a.infoid order by case idcardtype when 2 then 0 else 1 end)idcardtype1,
(select top 1 idcardno from 证件表 where infoid=a.infoid order by case idcardtype when 2 then 0 else 1 end)idcardno1,
(select top 1 idcardtype from 证件表 where infoid=a.infoid order by case idcardtype when 2 then 1 else 0 end)idcardtype2,
(select top 1 idcardtype from 证件表 where infoid=a.infoid order by case idcardtype when 2 then 1 else 0 end)idcardno2
from 人员表 a

[dairy1]

消息 156，级别 15，状态 1，第 4 行
Incorrect syntax near the keyword 'order'.

[playwarcraft]

--試下這個

select name,birthday,idcardtype1,idcardno1,
idcardcardtype2=(select top 1 idcardtype from 证件表 where infoid=T1.infoid and idcardtype<>T2.idcardtype1 order by idcardtype),
idcardno2 =(select top 1 idcardno from 证件表 where infoid=T1.infoid and idcardtype<>T2.idcardtype1 order by idcardtype)

from 人员表 T1
inner join
(select infoid,name,birthday,
idcardtype1=(select top 1 idcardtype from 证件表 where infoid=A.infoid order by case when idcardtype=2 then 1 else 2 end,idcardtype),
idcardno1=(select top 1 idcardno from 证件表 where infoid=A.infoid order by case when idcardtype=2 then 1 else 2 end,idcardtype)
from 人员表 A) T2
on T1.infoid=T2.infoid

[playwarcraft]

create table 人员表 (infoid int identity(1,1),name varchar(50),birthday datetime)
insert into 人员表  select 'a',getdate()
insert into 人员表  select 'b',getdate()
insert into 人员表  select 'c',getdate()
insert into 人员表  select 'd',getdate()
insert into 人员表  select 'e',getdate()

create table 证件表 (infoid int,idcardtype int,idcardno varchar(50))
insert into 证件表  select 1,2,'a11'
insert into 证件表  select 1,3,'a22'
insert into 证件表  select 1,4,'a33'

insert into 证件表  select 2,2,'b11'
insert into 证件表  select 2,3,'b22'
insert into 证件表  select 2,4,'b33'

insert into 证件表  select 3,4,'c33'

insert into 证件表  select 4,3,'d22'
insert into 证件表  select 4,4,'d33'
insert into 证件表  select 4,5,'d33'

select t1.name,t1.birthday,idcardtype1,idcardno1,
idcardcardtype2=(select top 1 idcardtype from 证件表 where infoid=T1.infoid and idcardtype<>T2.idcardtype1 order by idcardtype),
idcardno2 =(select top 1 idcardno from 证件表 where infoid=T1.infoid and idcardtype<>T2.idcardtype1 order by idcardtype)

from 人员表 T1
inner join
(select infoid,name,birthday,
idcardtype1=(select top 1 idcardtype from 证件表 where infoid=A.infoid order by case when idcardtype=2 then 1 else 2 end,idcardtype),
idcardno1=(select top 1 idcardno from 证件表 where infoid=A.infoid order by case when idcardtype=2 then 1 else 2 end,idcardtype)
from 人员表 A) T2
on T1.infoid=T2.infoid

/*
a	2008-03-04 10:11:38.340	2	a11	3	a22
b	2008-03-04 10:11:38.340	2	b11	3	b22
c	2008-03-04 10:11:38.340	4	c33	NULL	NULL
d	2008-03-04 10:11:38.340	3	d22	4	d33
e	2008-03-04 10:11:38.340	NULL	NULL	NULL	NULL

*/

drop table 人员表,证件表

[csshan]

1 楼的没问题，

[playwarcraft]

靈魂的當只有1個證件的時候，會重復到，