strncmp如何比较回车换行

[nancliu]

我有个字符串res，内容可能为'0x0d''0x0a''O''K'等等，我想通过strncmp比较其中内容是否为OK。使用strncmp(res,"OK")得不到正确的结果，请问有什么办法吗？

[sitnc]

const char* yourstring = "\nOK";
string str = yourstring;
if (string::npos != str.find("OK"))
{
cout << "include OK" << endl;
}

这样符合你的要求吗？

[珍惜生命远离CPP]

用strstr搜索一下。

[taodm]

当然是自己先把这些不算的字符先删了再比.

[nancliu]

字符串比较长，搜索的话很影响速度

[Chappell]

#include <string.h>
#include <stdio.h>

char str[] = "lazy";
char string[] = "The quick brown dog jumps over the lazy fox";
char fmt1[] = " 1 2 3 4 5";
char fmt2[] = "12345678901234567890123456789012345678901234567890";

void main( void )
{
char *pdest;
int result;
printf( "String to be searched:\n\t%s\n", string );
printf( "\t%s\n\t%s\n\n", fmt1, fmt2 );
pdest = strstr( string, str );
result = pdest - string + 1;
if( pdest != NULL )
printf( "%s found at position %d\n\n", str, result );
else
printf( "%s not found\n", str );
}

[nancliu]

搜索可能搜索到后面的“OK"

[nancliu]

用strncmp(res,"\r\nOK",4)可以吗？

[bsqsbylt]

strncmp(res,"\r\nOK",4)

[nancliu]

strncmp(res,"\r\nOK",4)可以用，虽然结果是16进制的