xml文件比较问题

[padababy]

有新旧两个xml文件需要尽行比较。
对于各个节点值，如果新旧不一致的话，取旧的。
最后 把结果输出来。
采用java，请做过的高手指点迷津，有代码最好，没有的话，思路也行。
谢谢！

[padababy]

有没有做过的，请教中。。。。。。。。。。。。

[dracularking]

和一般读取xml没什么区别
就是多了个比较的步骤
分别遍历两者节点 比较后输出

[padababy]

能举个例子吗，不是很清楚

[dracularking]

dom做的遍历document Text节点的 比较自己做吧

import java.io.File;
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.ErrorHandler;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;

class Test implements ErrorHandler {

    public static void main(String args[]) {
        Test test = new Test();
        test.go();
    }

    public void go() {
        Document doc = parseXmlFile("test.xml", true);
        visit(doc, 0);
    }

    // This method visits all the nodes in a DOM tree
    public static void visit(Node node, int level) {
        // Process node
        
        // If there are any children, visit each one
        NodeList list = node.getChildNodes();
        for (int i = 0; i < list.getLength(); i++) {
            // Get child node
            Node childNode = list.item(i);
            
            if(childNode != null && childNode.getNodeType() == Node.TEXT_NODE) {
                System.out.println(childNode.getTextContent());
            }

            // Visit child node
            visit(childNode, level + 1);
        }
    }

    // Parses an XML file and returns a DOM document.
    // If validating is true, the contents is validated against the DTD
    // specified in the file.
    public Document parseXmlFile(String filename, boolean validating) {
        try {
            // Create a builder factory
            DocumentBuilderFactory factory = DocumentBuilderFactory
                    .newInstance();
            factory.setValidating(validating);

            // Create the builder and parse the file
            DocumentBuilder db = factory.newDocumentBuilder();
            db.setErrorHandler(this);
            Document doc = db.parse(new File(filename));
            return doc;
        }
        catch (SAXException e) {
            // A parsing error occurred; the xml input is not valid
        }
        catch (ParserConfigurationException e) {
        }
        catch (IOException e) {
        }
        return null;
    }

    public void error(SAXParseException exception) throws SAXException {
        // TODO Auto-generated method stub

    }

    public void fatalError(SAXParseException exception) throws SAXException {
        // TODO Auto-generated method stub

    }

    public void warning(SAXParseException exception) throws SAXException {
        // TODO Auto-generated method stub

    }

}

<books> 
<book email="zhoujunhui"> 
<name> 
<name1>rjzjh</name1>
<name2>rjzjh2</name2>
<name3>rjzjh3</name3>
</name> 
<price> 
<price1>jjjjjj</price1> 
<price2>jjjjjj2</price2>
<price3>jjjjjj3</price3>
</price> 
</book> 
</books> 

[karlpan01]

var arrSignatures = new Array("MSXML.DOMDocument","Microsoft.XmlDom","MSXML2.DOMDocument","MSXML2.DOMDocument.3.0","MSXML2.DOMDocument.4.0","MSXML2.DOMDocument.5.0","MSXML2.DOMDocument.6.0"); 
  var oXmlDom;  
  for (var i = 0; i < arrSignatures.length; i++) {
    try {
      oXmlDom = new ActiveXObject(arrSignatures[i]);
      break;
    }
    catch (ex) { /* ignore */ }
  }
oXmlDom.async = false;
oXmlDom.loadXML(str);
oErr = oXmlDom.parseError;
if (oErr.errorCode != 0) {
		alert("解析XML数据错误：\n" + oErr.reason + "\nLine:" + oErr.line + "\nLinepos:" + oErr.linepos + "\nsrcText:\n" + oErr.srcText);

		return null;
}
创建DOM,读入xml/文件，在DOM对象中对读入的内容操作