java 对时间字串操作的问题，请高手指点！

[huangshua]

请问怎么把一个字符串的时间分成单独的年月日，再分别放入向应的变量中？
例如：
现有一字符串： 2005-5-6
怎么转化成：String nian=2005;
String yue=5;
String ri=6;
请高手指点！

[傻根她弟]

String dte = "2005-5-6";
String[] str = dte.split("-");
for(int j = 0;j<str.length;j++){
System.out.println(str[j]);
}

[Squall1009]

import java.util.StringTokenizer;

public class Test
{
	public static void main(String[] args) throws Exception
	{
		String str = "2005-5-6";
		String nian = null;
		String yue = null;
		String ri = null;
		StringTokenizer st = new StringTokenizer(str, "-");
		if (st.hasMoreElements())
			nian = st.nextToken();
		if (st.hasMoreElements())
			yue = st.nextToken();
		if (st.hasMoreElements())
			ri = st.nextToken();

		System.out.println("nian :" + nian);
		System.out.println("yue :" + yue);
		System.out.println("ri :" + ri);
	}
}

[bootupnow]

import java.util.*;
import java.text.*;

public class Test {
	
	public void parseDateTest()  {
		String d = "2005-5-6";
		DateFormat df = new  SimpleDateFormat("yyyy-MM-dd");		
		Calendar calendar = Calendar.getInstance();
		try{
			calendar.setTime(df.parse(d));
			int year = calendar.get(Calendar.YEAR);
			int month = calendar.get(Calendar.MONTH) + 1;
			int day = calendar.get(Calendar.DAY_OF_MONTH);
			System.out.println(year + " * " + month + " * " + day);			
		}catch(ParseException pe){
			pe.printStackTrace();
		}
	}
	
	public static void main(String[] args)   {
		new Test().parseDateTest();
	}
}

[bootupnow]

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