求组，汉字字节问题？

[mm85489949]

下面的代码中，我有个小问题？
比如100是壹佰元，1000是壹千元
现在怎么把个位数比如5，改成伍元后加个空也成3个字
Private Sub Command1_Click()
Text2 = ChMoney(Val(Text1))
End Sub

Private Function CCh(N1) As String
Select Case N1
Case 0
CCh = "零"
Case 1
CCh = "壹"
Case 2
CCh = "贰"
Case 3
CCh = "叁"
Case 4
CCh = "肆"
Case 5
CCh = "伍"
Case 6
CCh = "陆"
Case 7
CCh = "柒"
Case 8
CCh = "捌"
Case 9
CCh = "玖"
End Select
End Function
Public Function ChMoney(N1) As String
Dim tMoney As String
Dim lMoney As String
Dim tn '小数位置
Dim s1 As String '临时STRING 小数部分
Dim s2 As String '1000 以内
Dim s3 As String '10000

If N1 = 0 Then
ChMoney = " "
Exit Function
End If
If N1 < 0 Then
ChMoney = "负" + ChMoney(Abs(N1))
Exit Function
End If
tMoney = Trim(Str(N1))
tn = InStr(tMoney, ".") '小数位置
s1 = ""

If tn <> 0 Then
ST1 = Right(tMoney, Len(tMoney) - tn)
If ST1 <> "" Then
t1 = Left(ST1, 1)
ST1 = Right(ST1, Len(ST1) - 1)
If t1 <> "0" Then
s1 = s1 + CCh(Val(t1)) + "角"
End If
If ST1 <> "" Then
t1 = Left(ST1, 1)
s1 = s1 + CCh(Val(t1)) + "分"
End If
End If
ST1 = Left(tMoney, tn - 1)
Else
ST1 = tMoney
End If


s2 = ""
If ST1 <> "" Then
t1 = Right(ST1, 1)
ST1 = Left(ST1, Len(ST1) - 1)
s2 = CCh(Val(t1)) + s2
End If

If ST1 <> "" Then
t1 = Right(ST1, 1)
ST1 = Left(ST1, Len(ST1) - 1)
If t1 <> "0" Then
s2 = CCh(Val(t1)) + "拾" + s2
Else
If Left(s2, 1) <> "零" Then s2 = "零" + s2
End If
End If

If ST1 <> "" Then
t1 = Right(ST1, 1)
ST1 = Left(ST1, Len(ST1) - 1)
If t1 <> "0" Then
s2 = CCh(Val(t1)) + "佰" + s2
Else
If Left(s2, 1) <> "零" Then s2 = "零" + s2
End If
End If

If ST1 <> "" Then
t1 = Right(ST1, 1)
ST1 = Left(ST1, Len(ST1) - 1)
If t1 <> "0" Then
s2 = CCh(Val(t1)) + "仟" + s2
Else
If Left(s2, 1) <> "零" Then s2 = "零" + s2
End If
End If

s3 = ""
If ST1 <> "" Then
t1 = Right(ST1, 1)
ST1 = Left(ST1, Len(ST1) - 1)
s3 = CCh(Val(t1)) + s3
End If


If ST1 <> "" Then
t1 = Right(ST1, 1)
ST1 = Left(ST1, Len(ST1) - 1)
If t1 <> "0" Then
s3 = CCh(Val(t1)) + "拾" + s3
Else
If Left(s3, 1) <> "零" Then s3 = "零" + s3
End If
End If

If ST1 <> "" Then
t1 = Right(ST1, 1)
ST1 = Left(ST1, Len(ST1) - 1)
If t1 <> "0" Then
s3 = CCh(Val(t1)) + "佰" + s3
Else
If Left(s3, 1) <> "零" Then s3 = "零" + s3
End If
End If

If ST1 <> "" Then
t1 = Right(ST1, 1)
ST1 = Left(ST1, Len(ST1) - 1)
If t1 <> "0" Then
s3 = CCh(Val(t1)) + "仟" + s3
End If
End If
If Right(s2, 1) = "零" Then s2 = Left(s2, Len(s2) - 1)
If Len(s3) > 0 Then
If Right(s3, 1) = "零" Then s3 = Left(s3, Len(s3) - 1)
s3 = s3 & "万"
End If

ChMoney = IIf(s3 & s2 = "", s1, s3 & s2 & "元" & s1)

End Function

[mm85489949]

加个空格！

[用户 昵称]

这样

比如结果是s

dim l as long
l = leb( strconv( s, vbfromunicode ) )

设需要对齐100个长度

s = string( 100 - l, " " ) & s

[舉杯邀明月]

[Quote=引用 2 楼 jennyvenus 的回复:]
这样

比如结果是s

dim l as long
l = leb( strconv( s, vbfromunicode ) )

设需要对齐100个长度

s = string( 100 - l, " " ) & s
[/Quote]

不愧是高手！

“l = leb( strconv( s, vbfromunicode ))”中，leb 应该是 lenb 吧？

[vbman2003]

不明白你的意思，是不是要左对齐右对齐？

dim s as string * 10
lset s="一百元" '左对齐
debug.print s
rset s="五元" '右对齐
debug.print s