请高手帮我看一下，能不能帮我把这段代码改成JAVA，主要是指针不知道，谢谢！

[knifeczj]

void Gettexturefun(CImage * image,double *xf)
{
if (image->IsNull()) return;
int i,j;
int nWidth = image->GetWidth();
int nHeight = image->GetHeight();
int k;
k=0;
int **source = new int *[nWidth*2];
for (i = 0;i<nWidth*2;i++)
source[i] = new int [nHeight*2];

for (i = 0;i<nWidth*2;i++)
for ( j =0;j<nHeight*2;j++)
{
source[i][j]= 0;
}
double a[101][101];
for (i=0;i<101;i++)
for (j = 0;j<101;j++)
{ a[i][j] = 0;
}
for (i = 1; i< nWidth-1; i++){
for (j = 1; j < nHeight-1; j++){
int rr = 0, gg = 0, bb = 0;

COLORREF clr = image->GetPixel( i, j);
rr=GetRValue(clr);
gg=GetGValue(clr);
bb= GetBValue(clr);

rr = (int)(rr);
gg = (int)(gg);
bb = (int)(bb);
source[i][j] = int(0.3*rr+0.59*gg+0.11*bb);

// image->SetPixel(i-1,j-1,RGB(rr,gg,bb));

}
}
for (i=0;i<50;i++)
for (j=0;j<50;j++)
{ if (i==j)
{a[i][j] = PXY(i,j,source,nWidth,nHeight);}
}

for (i=1;i<50;i++)
for(j=1;j<50;j++)
{
if (i==j)
{ xf[k]= a[i][j]-a[0][0];
k=k+1; }
}

for (i = 0;i<nWidth*2;i++)
delete []source[i];
delete []source;


}

[arong1234]

学Java三天了，试试

void  Gettexturefun(CImage  image,double xf[]) 
{    
    if (image == null) 
    {
          return; 
    }
    int i,j; 
    int nWidth = image.GetWidth(); 
    int nHeight = image.GetHeight(); 
    int k; 
    k=0; 
    int  source[][] = new int [nWidth*2][nHeight*2]; 
     

   
    double a[101][101]; 
    for (i = 1; i < nWidth-1; i++)
    { 
       for (j = 1; j  < nHeight-1; j++)
       { 
             int rr = 0, gg = 0, bb = 0; 

             long clr = image.GetPixel( i, j); 
             rr=GetRValue(clr); //这个函数Java如果没有要加 
             gg=GetGValue(clr); 
             bb= GetBValue(clr); 
 
             source[i][j] = int(0.3*rr+0.59*gg+0.11*bb); //这行不确定能不能强制类型转换
      } 
    } 
    for (i=0;i <50;i++)
    { 
        for (j=0;j <50;j++) 
        { 
            if (i==j) 
            {
              a[i][j] = PXY(i,j,source,nWidth,nHeight);
            }
        } 
     } 

     for (i=1;i <50;i++) 
     {
       for(j=1;j <50;j++) 
       { 
          if (i==j) 
          { 
             xf[k]= a[i][j]-a[0][0]; 
             k=k+1; 
           }
       } 
     }      
 }